I assume that we are multiplying these terms together ???? ......if so......
Notice that this can be written as :
6 ^ [ 1/2 + 1/4 + 1/8 + 1/16.......]
And the sum, S, of this series can be found thusly :
S = a / [ 1 - r) where a is the first term = 1/2 and r is the common ratio between successive terms = 1/2
So we have
S = (1/2) / ( 1 - 1/2) = (1/2) /(1/2) = 1
6 ^ [ 1/2 + 1/4 + 1/8 + 1/16.......] =
6^ [1] =
6
...
