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First question.....

We need to find the effective rate of daily depreciation, thusly...

(.90)^t  = (r)^(365t)    take the log of both sides

log(.90)^t  = log(r)^(365t)

(t) log(.90)  = (365t)log(r)

(1/365) log(.90)   = log(r)

10^[(1/365) log(.90) ]  = r  = ..9997

So....the correct expression is :

22000(,9997)^(365t)   and the value after 5 years = about $13000

So (b) is the correct answer

square root of 30 is between 5 and 6, but closer to 5.

A^2+b^2=C^2

5^2+b^2=13^2

25+b^2=169

b^2=144

b=12

Thanks Spawn  LOL

5-1=4

2*5-6*5=20

2*5=10-6=4*5=20

Throwing 12 dice and getting at least two  6's =

1 - P(no 6's) - P( one 6)  =

1 - (5/6)^12 - C(12,1)(1/6)(5/6)^11  =  about 61.9%

Throwing 18 dice and getting at least three 6's =

1 - P(no 6s) - P(one 6) - P( two 6s)  =

1 - (5/6)^18 - C(18,1)(1/6)(5/6)^17  - C(18,2)(1/6)^2(5/6)^16  =   about 59.7%

Thus....the first thing is slightly more likey to happen....

1779, Why not use a calculator it would be so much faster.

(Lenght*Width)/2

Wich is better sell ur 360 to buy a ps3 at gamesstop or just trade it

You can go to this link and see if it will help you:

http://www.nationalgeographic.com/geobee/study-corner/activity-18/

A = length times width all over 2.

As a formula, it is:

A = (L*W)/2

Lmao


According to a Cornell publication, the answer is ~700 pounds.    Excerpt:
 

How much wood could a woodchuck chuck if a woodchuck could chuck wood?
 

About 700 pounds.

Compared to beavers, groundhogs/woodchucks are not adept at moving timber, although some will chew wood. (At Cornell, woodchucks that gnaw their wooden nest boxes are given scraps of 2-by-4 lumber.) A wildlife biologist once measured the inside volume of a typical woodchuck burrow and estimated that -- if wood filled the hole instead of dirt -- the industrious animal would have chucked about 700 pounds' worth.

Source: http://www.news.cornell.edu/Chronicle/96/2.1.96/facts.html

The intensity, Io, of a light source is reduced to I after passing through d meters of fog according to the formula I = Ioe−0.12d. If 1,200 lumens of light are present initially, what is an equivalent expression written as a percentage rate of lumens lost?

Hint: Find the value of e−0.12 on your calculator.

a) I = 1,200ed I = 1,200(0.887)d 

b) I = 1,200e0.88d I = 1,200(0.88)d

c)I = 1,200ed I = 1,200(0.887)d 

d)I = 1,200e0.88d I = 1,200(0.88)d

Already answered here :  http://web2.0calc.com/questions/help_50278

[114 + 1/8]  - [ 107 + 3/4]   

[113 + 9/8]  - [107+ 6/8]  =

[113 - 107] + [ 9/8 - 6/8] =

6 + 3/8   lbs.   more 

2, becaus not only are you throwing more dice, but you also have more chances to get another 6.

But if not than probably 1

Well...if the x is an exponent thusly  :   500(1.04)^x

Then, 2 would seem reasonable  [ the total amount of money after x years on a $500 investment paying 4% annual interest ]