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\(x-\frac{4}{-1}=x+4 \)

\(x+4=0 \)

\(x=-4\)

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yup

Volume of the sphere  =

(4/3)* pi  *(4)^3 =  about 268.08 cm^3

Volume of the cylinder =

pi *  (3)^2  * (5)  = about 141.37 cm^3

The sphere has almost twice the volume of the cylinder

okay thanks

(x^3 - 3x^2 + 2x + 5)  

           (x + 2)

Here....I can't tell if the top is  factorable, or not.....polynomial long division is the method that would work the best...

           (  x^2  - 5x + 12  )

x + 2   [ x^3  - 3x^2 + 2x + 5 ]

             x^3  + 2x^2

            ----------------------------

                      -5x^2  + 2x

                      -5x^2  -10x

                     -----------------

                                12x + 5

                                 12x + 24

                                 ------------

                                         -19

So......the answer is       x^2 - 5x + 12  and a remainder of  -19 / [x + 2]

not really I don't think you got the question. let me give you the problem maybe you could explain it better if I showed you what I mean

(x^3 - 3x^2 + 2x + 5)

           (x + 2)

(8.76*10^9) (6.52*10^-3) /  [13.27*10^5]

Let's divide this up as :

(8.76 * 6.52) / (13.27)        x      (10^9 * 10^-3) / (10^5)   =

≈ 4.304     x    [  10^6 / 10^5 ]  =

≈ 4.304   x 10 

If you mean 2(x-2) then yes, Elizabeth is correct. as it would be 2x-4.

If you mean (x-2)² then no, CPhill is correct. :)

1 3/4

In this case, Katie, it was easy to split up the terms and divide them individually since the denominator was only one term.......this may not always work so well it we were dividing by more than one term  [such as x + 2 ]

Another approach is to see if we could factor the top.....this is usually preferable...sometimes, we get a factor that "cancels" with the denominator with this method.....let's try it that way :

(20x^4 + 5x^3 - 10x^2 + 30x)        =      5x ( 4x^3 + x^2 - 2x + 6)

                    5x                                                5x

Note that, now.......the "5x's"   would "cancel"  and we would be left with my original answer.......this "factor and cancel" method is usually good to try when we're dividing by more than one term......!!!!!

Of course....polynomial "long division" would always give us the correct answer......[there may be a remainder, in some cases, though ]

Does that help ???

okay thank you CPhill is this the same when you have a number such as say the same number but instead of deviding it by 5x it's devided by (2+x)?

(20x^4 + 5x^3 - 10x^2 + 30x)

________________________

                    5x

Note, Katie,  that we can break this up as:

20x^4 / 5x    +  5x^3 / 5x   -  10x^2 / 5x  + 30x / 5x     =

4x^3 +    x^2    -  2x   +  6

Let  x  =  0.54 54 54 54 54 ...

Then multiply by 100, because 100 will move the repeating digits to the left one cycle (two places):

   100 x  =  54. 54 54 54 ...     Now subtract the original value:

          x  =    0. 54 54 54 ...

     99x  =  54                         Finish by dividing by 99:

         x  =  54/99                   Reduce:

        x  =  6/11

I think I have the idea, FM......

We have two  congruent right triangles.....where BA  is the leg of one [ and BC is the corresponding congruent leg of the other right triangle ]

The distance from the center of the Earth to the satellite  is the hypotenuse of both  triangles =

[ 6360  +  720] km  = 7080 km

And the radius of the Earth - 6360 km -  forms the other congruent leg of both right triangles....

So...BA is the remaining unknown leg of one of the right triangles

BA  = √ [ 7080^2  - 6360^2 ]   = about 3110.76 km        [ this also = BC ]

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No...she made the common error of distributing the exponent over both terms in the parentheses.....this is incorrect......it should be.....

(x - 2)^2   =

(x - 2) (x - 2)  =

x^2 - 2x - 2x +4  =

x^2 - 4x + 4

42, naturally. 

I don't think the calculator can do that, but this website can :

http://www.wolframalpha.com/input/?i=slope+%281,4%29,+%285,3%29

Just type :     slope (-4, 0) , (2, -4)     and hit enter

10x^3+5x^2-20x      if you're are tyrying to find the roots, we have

10x^3+5x^2-20x  = 0    factor

(5x) ( 2x^2 + x - 4)       x = 0   is one root

Using the quadratic formula, the other two are :   x =   [ 1 ±√33 ]  / 4