Two perpendicular chords with lengths 12.2 cm and 8.8 cm have a common endpoint.What is the area of the circle?
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If the chords are perpendicular, they form a right angle, and in a circle, an inscribed angle measures 1/2 of its intercepted arc. So, the arc it intercepts is a half-circle. Thus the remaining side of this right triangle (the hypoteneuse) is a diameter.
So (12.22 + 8.82)(1/2) ≈ 15.04 cm And half of this is the raius of the circle = 7.52
And the area of the circle is pi*(7.52)2 ≈ 177.66cm2
