Hallo Guest
The denominator must not 0 (null).
The denominator is 0, if
\(\begin{array}{rcll} x+1 &=& 0 \quad & | \quad -1\\ x+1-1 &=& 0-1 \\ x+0 &=& -1 \\ x &=& -1 \end{array}\)
so \(x=-1\) is not permissible or \(D = R ~ \backslash ~ \{-1\}\)

\(\dfrac{-2x+3}{x+1} > 1\)


