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Sin 1/2Q=0.4 How do i find the value of Q?

Sin [1/2Q]=0.4

Arcsin(.4) =23.58 degrees

Sin[1/2Q] =23.58

Q=23.58 x 2

Q=47.16

no clue!!!!

Divide by -3

nvm, I figured it out

it is (4,0) (0,0) and (0,0)

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Force is mass times acceleration, so just multiply the numbers together.  With the specified units for mass and acceleration the force will be in Newtons.

81^0.25 = 3

2^-1 = 1/2

Can you take it from here?

Let a, b and c be the side lengths with c being the longest.  

If c^2 > a^2 + b^2 the triangle is obtuse.

If c^2 < a^2 + b^2 the triangle is acute.

Your question needs to be more specific.   ://

So the answer is 5 km south !

Show that    x^2+90x-1200=0

I can't cause it doesn't.  I mean it might sometimes but it very rarely would.

I think the question is supposed to be

Find when   x^2+90x-1200=0

Or

Solve for x:    x^2+90x-1200=0

I'd use the quadratic formula to solve this.

\(\triangle =b^2-4ac \\ \triangle = 8100+4*1200\\ \triangle =8100+4800\\ \triangle =12900\\ x=\frac{-90\pm\sqrt{12900}}{2}\\ x=\frac{-90\pm10\sqrt{129}}{2}\\ x=-45\pm5\sqrt{129}\\\)

9p^8x2q^14/18q=9p^8+?

I have taken th liberty of adding brackets as this is what I think you mean ...

9p^8 x 2q^14/(18q)=9p^8+?

\(\frac{9p^8*2q^{14}}{18q}=9p^8+Z \qquad find\;Z\\ Z=\frac{9p^8*2q^{14}}{18q}-9p^8\\ Z=\frac{p^8q^{14}}{q}-9p^8\\ Z=p^8q^{13}-9p^8\\ or\\ Z=p^8(q^{13}-9)\)

thank you :)

simplify 5a x 6b=30ab. That is it.

Simplify the following:
(9×2 p^8 q^14)/(18 q)

9/18 = 9/(9×2) = 1/2:
(2 p^8 q^14)/(2 q)

(2 p^8 q^14)/(2 q) = 2/2×(p^8 q^14)/q = (p^8 q^14)/q:
(p^8 q^14)/q

Combine powers. (p^8 q^14)/q = p^8 q^(14-1):
p^8 q^14-1

14-1 = 13:
Answer: |  p^8 x q^13

5a6b

ohhh, that makes a lot more sense :) Thanks guys :D

Do you mean formulas for four sided shapes/prisms?

The "l" in "ln" is a lower case L not an upper case "i"!!  Unfortunately, The two look identical in many fonts!

It is NOT "in"!!!!. It is "Ln", which stands for "Natural Log" to base "e=2.718281828..........", instead of "base 10".

You are correct.  The ln means the natural logarithm; that is, logarithm to the base e.  However you could use logarithm to the base 10 if you prefer (as long as you use the same base for both the 925 and the 3).

(You should find t is just over 6.)

So the answer is 75+3^t =1000 accounts

Therefore 3^t=925 years. Correct?