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11.13

(-200000*e^2.5)*(-0.5) ?

\(\begin{array}{rcll} ( -200000\cdot e^{2.5} )\cdot(-0.5) &=& ( 200000\cdot e^{2.5} )\cdot(0.5) \quad & | \qquad (-)\cdot(-) = (+) \\ &=& ( 200000\cdot e^{2.5} )\cdot(\frac12) \\ &=& \frac{200000}{2} \cdot e^{2.5} \quad & | \qquad e^{2.5} = 12.182493960703471\dots\\ &=& 100000 \cdot e^{2.5} \\ &=& 100000 \cdot 12.182493960703471\dots \\ \mathbf{( -200000\cdot e^{2.5} )\cdot(-0.5) }&\mathbf{=}& \mathbf{1218249.3960703471\dots} \end{array}\)

x^2+3x+4=0 what does the x equal? please solve

\(\boxed{~ \begin{array}{rcll} ax^2+bx+c &=& 0\\ x &=& \dfrac{-b \pm \sqrt{b^2-4ac}} {2a} \\ \end{array} ~}\)

\(\begin{array}{rcll} x^2+3x+4 &=& 0 \qquad & a=1 \quad b=3 \quad c = 4 \\\\ x &=& \frac{-3 \pm \sqrt{3^2-4\cdot 1 \cdot 4} }{2\cdot 1} \\\\ x &=& \frac{-3 \pm \sqrt{9-16} } {2} \\\\ x &=& \frac{-3 \pm \sqrt{-7} } {2} \qquad &| \quad \sqrt{-7}=\sqrt{-1\cdot 7}=\sqrt{-1}\sqrt{7}\\\\ x &=& \frac{-3 \pm \sqrt{-1}\sqrt{7} } {2} \qquad &| \quad \sqrt{-1} = i \\\\ x &=& \frac{-3 \pm i\sqrt{7} } {2} \\\\ \mathbf{x_1} &\mathbf{=}& \mathbf{-\frac32 + \frac{\sqrt{7}}{2}\cdot i } \\\\ \mathbf{x_2} &\mathbf{=}& \mathbf{-\frac32 - \frac{\sqrt{7}}{2}\cdot i } \end{array}\)

Algebra 1.

For f = { (-5,2), (-4,-1), (3,-8), (-2,0), (4,-9) } find the indicated value.

f(-4) =-1 _______(-4,-1)___________________

f(3) = -8________(3,-8)___________________

f(4) = -9________(4,-9)___________________

f(-5) =2 ________(-5,2)___________________

61 is prime so the only numbers that divide it are 1 and 61

Note to Admin: Urgent need for “Batshit-Stupid” label.

 Landry : Zero is not a number. A number is a value or the symbol

representing a value. Zero has no value.

Zero does have a value –it’s zero (0), Just as one has a value of one (1), and two has a value of two (2).

Zero is a real number. It exists on the number line between one (1) and negative 1 (-1). Using zero in functions of addition, subtraction, and multiplication return real numbers. Dividing zero by a real number returns a real number of zero. 

Landry: Zero is not a number, but an independent entity.

It is an anti-number, and it is nothingness, so it can not be positive or negative.

Landry, You will end up with a big ZERO of nothingness and anit-reality unless you avoid learning mathematical concepts in liberal arts classes. Reality in that universe is very different from this one.

solve for x, can use quadratic formula, factoring, completing the square etc.

http://www.dummies.com/how-to/content/how-to-factor-a-polynomial-expression.html

doesn't factor, use quadratic formula or complete the square

completing the square:

x^2+3x+4 = 0    Note: ax^2+bx+c (a, b & c are constants not variables like x)

x^2+3x = -4

x^2+3x+2.25=-4+2.25    Note: (b/2)^2 = c   3/2 = 1.5, 1.5^2 = 2.25 (add 2.25 to both sides to keep the equation the same)

(x+1.5)^2 = -1.75     Note:  x^2+3x+2.25 using complete the square is (x+1.5)^2

sqrt(x+1.5^2)= sqrt(-1.75)   Note: Again, same operation to both sides, square root to keep the equation the same

x+1.5 = (plus or minus) sqrt(-1.75)

x = (plus or minus) sqrt(-1.75) - 1.5

carry negative sign* it does exist just not a real number it is an imaginary number

solve for x, can use quadratic formula, factoring, completing the square etc.

http://www.dummies.com/how-to/content/how-to-factor-a-polynomial-expression.html

doesn't factor, use quadratic formula or complete the square

completing the square:

x^2+3x+4 = 0    Note: ax^2+bx+c (a, b & c are constants not variables like x)

x^2+3x = -4

x^2+3x+2.25=-4+2.25    Note: (b/2)^2 = c   3/2 = 1.5, 1.5^2 = 2.25 (add 2.25 to both sides to keep the equation the same)

(x+1.5)^2 = 1.75     Note:  x^2+3x+2.25 using complete the square is (x+1.5)^2

sqrt(x+1.5^2)= sqrt(1.75)   Note: Again, same operation to both sides, square root to keep the equation the same

x+1.5 = (plus or minus)sqrt(1.75)

x = (plus or minus)sqrt(1.75) - 1.5

There can only be one guest

If 5z+7 = 12z-2, then z= 

7z=9 divide both sides by 7

z=9/7 or "A"

2,587,221

impossible. graph it.

Plugging this into WolframAlpha gives me this (admittedly dubious) answer.

x = 1/2*i*(sqrt(7)+3i

x = 1/2*i*(sqrt(7)-3i

im coooooooooooooool

Solve for h:

3 h^2+2 h-16 = 0

The left hand side factors into a product with two terms:

(h-2) (3 h+8) = 0

Split into two equations:

h-2 = 0 or 3 h+8 = 0

Add 2 to both sides:

h = 2 or 3 h+8 = 0

Subtract 8 from both sides:

h = 2 or 3 h = -8

Divide both sides by 3:

Answer: | h = 2 or h = -8/3

I helped.