\(2\times\sqrt{2}\times(-\sqrt{12})\)
Since \(\sqrt{2}\) and \(\sqrt{12}\) are not perfect squares, instead of finding what \(\sqrt{2}\) and \(\sqrt{12}\) are, expand the terms inside the radicals to find perfect squares:
\(2\times\sqrt{2}\times\sqrt{12}\)
\(2\times\sqrt{2}\times\sqrt{4\times3}\)
\(2\times\sqrt{2}\times\sqrt{2\times\times2\times3}\)
\(2\times\sqrt{2}\times2\times\sqrt{3}\)
\(2\times\sqrt{2}\times2\times\sqrt{3}\)
\(4\times\sqrt{2}\times\sqrt{3}\)
\(4\times\sqrt{6}\)
\(4\sqrt{6}\)
If you want an approximate answer:
\(2\times\sqrt{2}\times\sqrt{12}\)
\(2\times 1.414213562373095\times\sqrt{12}\)
\(2.82842712474619\times\sqrt{12}\)
\(2.82842712474619\times3.4641016151377546\)
\(9.797958971132712091295411504974\)
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