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56633031892129

Dear algebra, 

Please stop asking me to find your X, she's not coming back to you.

lol

If Rage's money is 75p and is 1/3 of the total, then he must have:

75p/(1/3)=75 x 3 =2.25 pounds. 3/8 of that amount is:

2.25 x 3/8=6.75/8=.84375p

Me either 

When you have a problem of this type, just state the problem in words and we will show you how to solve it and give you the correct formula. The formula you have given doesn't make any sense, the way you have it written down.

I haven't been on here in awhile.... XD

Thank you 

After each press the new copy would be reduced to 0.88 times its size before the press.

After 5 presses the size would be 8*0.88^5  =   4.22 inches

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This goes to log(2)/log(0) and since log(0) is -infinity the limit goes to 0.

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MINE WAS AWESOMMMMEEEE!!  (Hyper,  H7 is Hyper xD)

Thanks for asking.

And get a better knee....I mean hope your knee gets better *facepalm*

~Jackbanks

I feel your frustration, if you think they are confusing, but they get easier as you go along.Here is my definiton of an algebraic expression-

In mathematics, an algebraic expression is an expression built up from integer constants, variables, and the algebraic operations (addition, subtraction, multiplication, division and exponentiation by an exponent that is a rational number). For example,  2x+3y+6

~FAFA11032000

Mine was great thank you.

Hope your knee feels better!

~Songoflight

It's a typo!!!! I meant was. Mine was good but I hurt my knee 

put in terms of x  0 :

log(2) = 0.3010299956639812

Answer: 0.301

'2nd" button "acos"

atan(2+sqrt(3) = 75

\(4+7(n-1)\)

it is unsolveble but if you will take them one by one:

2x=-6

x=-3

2x=10

x=5

(-n)(n) = -n * n

           = - n²

That is a much better answer.

Thanks Chris :)

simplify the square root of 144g to the power if 8

\((\sqrt{144g})^8\\ =(\sqrt{144}*\sqrt{g})^8\\ =(12*\sqrt{g})^8\\ =12^8*(\sqrt{g})^8\\ =12^8*(g^{1/2})^8\\ =12^8*g^{(1/2)*8}\\ =429\;981\;696\;g^{4}\\\)

Just hit the " = "  twice

The sufrace area, S, of the box will  = b^2 + 4bh   where b is the side of the base and h is the height  and this will =  12ft^2

The volume, V  = b^2 *h

So ....  we have the two equations

12 = b^2 + 4bh

V  = b^2* h

We can solve for the height in the first equation and sub this into the second

12- b^2  = 4bh

h = [12  - b^2]  / 4b

So....the volume is given by

V(b) = b^2 [12  - b^2]  / 4b   =  b[12 - b^2]/4  =  3b - (1/4)b^3

Taking the derivative of this we have

V ' (b)  = 3 - (3/4)b^2     set this to  0

3 - (3/4)b^2  = 0

3 = (3/4)b^2      divide through by 3

1 = (1/4)b^2      multiply both sides by 4

4 = b^2     take the positive root

2  feet = b

And h = [12  - 2^2]  / 4(2)  =  [8] / [8]  = 1 ft

So  a box with a square base of 2 ft on each side and 1 ft high will produce the max volume = b^2*h  =  (2)^2* (1)   =  4ft^3

Here's a graph of the volume where h is in terms of b :  https://www.desmos.com/calculator/27nqcjdoy7

Note that the max volume occurs when b = 2 ft   [ and, by implication, h = 1 ft ]

Thank you very much