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An insect population is increasing at a rate of e^(t/4) insects per day. Find the size of the insect population after 10 days assuming that there are 100 insects at time t=0 days.
100 x e^(10/4)=1,218-insect population after 10 days.
5/7 x 14 =70/7=10
Depends on when the interest gets paid really.
25 * 1.06 will give you the interest added once.
If interest is added every month you have to take into account the previously added interest so to easily calculate this just do:
25 * 1.06^x where x stands for the number of times interest is added.
So if interest is added every month then over a single year it would be:
25 * 1.06^12 = 50.3 (3.d.p)
= $50.30
how do I rewrite 4.8 times 10 to the power of two times ten to the power of five with a single power of ten
4.8 x 10^2 x 10^5=48,000,000=4.8 x 10^7
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$340,067,388,803,148,021,760.00. + $683,569,801,735,620,788,224.00 = $1,023,637,190,538,768,809,984
Is it really that hard to put this into the calculator on this website?
A + B=10
2[10A + B] - 1=10B + A
So the original number is=37
Solve the following system: {A+B = 10 | (equation 1) 2 (10 A+B)-1 = A+10 B | (equation 2) Express the system in standard form: {A+B = 10 | (equation 1) 19 A-8 B = 1 | (equation 2) Swap equation 1 with equation 2: {19 A-8 B = 1 | (equation 1) A+B = 10 | (equation 2) Subtract 1/19 × (equation 1) from equation 2: {19 A-8 B = 1 | (equation 1) 0 A+(27 B)/19 = 189/19 | (equation 2) Multiply equation 2 by 19/27: {19 A-8 B = 1 | (equation 1) 0 A+B = 7 | (equation 2) Add 8 × (equation 2) to equation 1: {19 A+0 B = 57 | (equation 1) 0 A+B = 7 | (equation 2) Divide equation 1 by 19: {A+0 B = 3 | (equation 1) 0 A+B = 7 | (equation 2) Collect results: Answer: | A = 3 and B = 7
Use this symbol: / or simpy use division
e.g 1/5 will show up as 1 over 5
There is also an input helper. Use the dropdown list on the right of the input box and select fractions
230.86 / 23.8 =9.7 inches-half of the base.
9.7 x 2 =19.4 inches-the length of the base.
25 x 6/100 =1.50 pounds - interest for 1 full year.
that would be 25£x1.06 for a whole year of profit. But it depends on how long has it been in the bank. If you would say six months, it would be 25£x1.066/12
Or basically anything less than 1.
It makes sense that if you were to divide (put) the number 10 into 2 piles, you would get 5 in each pile.
If you put 10 into 1 pile, you would get 10 in each pile.
If you put 10 into half a pile (divide by 0.5), the pile would have 20 in it; your original number just made up half of that pile.
Hope you got that and that this helped!
By dividing by a decimal.
Ex. 14/.5=28
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solve 2(x-3)=4x
2x - 6 = 4x
-6=4x - 2x
2x=-6 divide both sides by 2
x=-3
=5.185653... × 10^94
=1/(5000 sqrt(10))
