So basically what we have here is a rectangle on the bottom part, and then a half circle on the upper part. We'll need to add these two areas together to get the total area.
For the area of the rectangle, simply multiply 6 in times 2 in (base times height), giving you \(12\; in^2\).
For the half circle, we know that the area of a circle is pi times the radius^2. Well, we don't know the radius but we do know the diameter of this circle, which is 6 in. The radius is always half the diameter, so the radius is 3 in.
Meaning, the area of this half circle is 1/2(pi((3 in)^2)) =
\(\frac{9}{2}\pi\; in^2\)
or aproximately
\(14.13\; in^2\)
Adding these together we get aproximately
\(28.13\; in^2\)
Which, if we're rounding to the nearest inch, would come out to
\(28\; in^2\)
Thanks for the question dude. If you have any additional questions or don't understand how I did this, or even see a mistake of mine, feel free to let us know and me or another forum member would love to help!
