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There is no algorithm that can solve the travelling salesman's problem, especially for a large number of cities, because it is considered an "NP-Hard" problem. As of now, simulations on supercomputers is used to get an approximation for the solution.

10/10

15 gal 

If it is compounded and added annually then

\(FV=626.40*(1+0.08)^1\\ FV=626.40*1.08\\ FV=$676.51 \)

I've spent ages trying to work out what this information is telling me.

I don't understand the margin of error so I have ignored it.   :/

I think this is what I am being told.

There were 3 samples of 40 people where 25 of the 40 were unhappy with the government.

There were 6 samples of 40 people where 26 of the 40 were unhappy with the government.

etc

You are not really being asked for the sample mean.  I think that the wording of the question is really poor because you are given the sample means for each of the 40 samples.  

What they really want you to find is the mean of the sample means.

Now there are 3 sample  25 dissatisfied people.  that is a total of 3*25=75 dissatisfied people in this 3 samples.

There are 6 samples with 26 dissatisfied people that is a total of 6*26=75 dissatisfied people in this 6 samples.

If you keep going like this you get a total of 2981 dissatisfied people in the 100 samples.

So the average number of dissatisfied people per sample is    2981/100 = 29.81 people

The percentage of dissatisfied people in these samples is  29.81people per 40 person sample.

\(\mbox{The percentage of dissatisfied people } =\frac{29.81}{40}*100\%=\frac{2981}{40}\%=74.52\%\)

So I believe that the last one is the answer.     

If you have questions about what I have done,  please ask

i sent full version of the problem again you can see top of the questions now:) i am sorry its my fault

There is no distinct question here so no one is going to be able to answer.   :(

100 Grad = 90 Degrees, so multiply the number of degrees by 100/90 to get the result in grads.

There is no question here  :/

Plus the wording is confusing.    

\(\frac{60 - 55}{60} = \frac{5}{60} = \frac{1}{12}\)          

The graph below should help:

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Assuming it's a regular polygon we have  180*n - 360 = 1440  or n = 10, so it's a ten sided polygon (a decagon).

There are two prime factors of 93, namely 3 and 31.  

\(\frac{1km}{1000m}=\frac{20km}{x}+8m\)

\(1km\times x=20km\times1000m+8m\)

\(1\times x=20000m+8m\)

\(x=20000m+8m\)

\(x=20008m\)

\(\sqrt{5}\times\sqrt{2x-1}\)

\(\sqrt{5\times(2x-1)}\)

\(\sqrt{10x-5}\)

Hi Mellie

I can't find your invisable post.

How long ago did you post it?

Maybe you should just post it again ://

Thanks! :)