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log25+log2xlog50+(log2)^2=?

Vielen Dank asinus.

(Thank you asinus)

The volume of a cone w a height of 12 in. is 144pi cubic inches.

What is the length in inches, of the diameter of its base?

\(h_{\text{cone}} = 12\ in.\\ V_{\text{cone}} = 144\cdot \pi\ in^3 \\ d_{\text{cone}} = 2\cdot r \\ r = radius\)

\(\begin{array}{rcll} \frac13 \cdot \pi \cdot r^2 \cdot h &=& V_{\text{cone}} \qquad &| \qquad h = 12 \quad V=144\cdot \pi\\ \frac13 \cdot \pi \cdot r^2 \cdot 12 &=& 144\cdot \pi \qquad &| \qquad :\pi \\ \frac13 \cdot r^2 \cdot 12 &=& 144 \qquad &| \qquad 144 = 12\cdot 12 \\ \frac13 \cdot r^2 \cdot 12 &=& 12\cdot 12 \qquad &| \qquad : 12 \\ \frac13 \cdot r^2 &=& 12 \qquad &| \qquad \cdot 3 \\ r^2 &=& 12 \cdot 3 \\ r^2 &=& 36 \qquad &| \qquad 36= 6\cdot 6 \\ r^2 &=& 6\cdot 6 \\ r^2 &=& 6^2 \qquad &| \qquad \sqrt{()} \\ r &=& 6 \\\\ d &=& 2\cdot r \\ d &=& 2\cdot 6 \\ \mathbf{ d }& \mathbf{=} & \mathbf{12\ in.} \end{array} \)

The diameter of its base is 12 in.

Spitze heureka! Greeting asinus :- )

log25+log2xlog50+(log2)^2=?

\(\small{ \begin{array}{rcll} && \log(25)+ \log(2) \cdot \log(50)+[\log(2)]^2 \\ &=& \log(5^2)+ \log(2) \cdot \log(2\cdot 5^2)+ \log(2)\cdot \log(2) \\ &=& 2\cdot\log(5)+ \log(2) \cdot [~ \log(2) +\log(5^2) ~]+ \log(2)\cdot \log(2) \\ &=& 2\cdot\log(5)+ \log(2) \cdot \log(2) + \log(2)\cdot\log(5^2)+ \log(2)\cdot \log(2) \\ &=& 2\cdot\log(5)+ 2\cdot \log(2) \cdot \log(2) + \log(2)\cdot\log(5^2)\\ &=& 2\cdot\log(5)+ 2\cdot \log(2) \cdot \log(2) + 2\cdot \log(2)\cdot\log(5)\\ &=& 2\cdot\log(5)+ 2\cdot \log(2) \cdot [~ \log(2) + \log(5) ~]\\ &=& 2\cdot\log(5)+ 2\cdot \log(2) \cdot \log(2\cdot 5) \\ &=& 2\cdot\log(5)+ 2\cdot \log(2) \cdot \log(10) \qquad | \qquad \log_{10}(10) = 1\\ &=& 2\cdot\log(5)+ 2\cdot \log(2) \cdot 1\\ &=& 2\cdot\log(5)+ 2\cdot \log(2) \\ &=& 2\cdot [~ \log(5)+ \log(2) ~] \\ &=& 2\cdot \log(5\cdot 2) \\ &=& 2\cdot \log(10) \qquad | \qquad \log_{10}(10) = 1\\ &=& 2\cdot 1\\ &=& 2 \\ && \mathbf{ \log(25)+ \log(2) \cdot \log(50)+[\log(2)]^2 = 2 } \end{array} } \)

Hello Guest!

log25+log2xlog50+(log2)^2=?

log25 + log2 x log50 + (log2)²

    = 1,39794000867 + 0,301029995664 x 1,69897000434

       + 0,301029995664²

    = 2

log25 + log2 x log50 + (log2)² = 2

Greeting asinus :- )

  !

Volume of cone=pi. r^2. h/3

144pi =pi x r^2 x [12/3] divide both sides by 4pi

36=r^2 take the square root of both sides.

r=6 inches-the radius of its base

6 x 2=12 inches- the diameter of the base.

what is the answer to the problem 87 less than the quotient of an unknown number and 43 is -75.

Why did you use the word "quotient of an unknown number?" A quotient is the result of the division of one number or quantity by another.

let the number be=x
x - 87 + 43 =-75

x=-75 + 87 - 43

x= -31

The EXACT probability is:85,228 / 6^10=0.00140951529662......Your task is to figure out how to arrive at these numbers!!!.

Two/2

I believe your way is correct.

Even if your teachers way had merit it would be addition not multiplication.

But your way is correct otherwise you'd be double counting :) 

At its most basic definition, N+1 simply means that there is a power backup in place should any single system component fail. The 'N' in this equation stands for the number of components necessary to run your system. The '+1' means there is one independent backup should a component of that system fail.Dec 12, 2012

Where are your 2 plans?

what the hack you are the website ask them  btw it is 2

Solve for x:
6-2 (5 x+3) = -37

-2 (5 x+3) = -6-10 x:
6+-6-10 x = -37

Grouping like terms, 6-6-10 x = (6-6)-10 x:
(6-6)-10 x = -37

6-6 = 0:
-10 x = -37

Divide both sides of -10 x = -37 by -10:
(-10 x)/(-10) = (-37)/(-10)

(-10)/(-10) = 1:
x = (-37)/(-10)

The sign of (-37)/(-10) is positive, so (-37)/(-10)  =  1×37/10:
Answer: |  x = 37/10

Thank you 4 answering! I posted the question

I posted same question may 9th!

0 3-3=0x6-2-0 because anything times zero is zero.

how much money do you have?