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how you solve this -5.7(-32.5)-(-2.9)= ?

      -5.7(-32.5)-(-2.9)=188.15

Probability of A = probability of picking a male who likes chocolate ice cream  = 3/75

Probability of B = probability of picking a female who doesn't lke ice cream at all  = 1/75

P (A ∩ B )  =  3/75 * 1/75   = 3 / 5625   = about .053 %

Members of the lake Shawnee Club pay $40 presumer season plus $7.50 each time they rent a boat. Non members pay 12.50 each time they rent a boat. How many times would it take for bot a member and a non member to pay the same amount.

Let the number of boat rentals=N,

40 + 7.5N =12.5N

40 =12.5N - 7.5N

40=5N divide both sides by 5

N=40/5

N=8 times when both will pay the same amount.

Thanks for that answer, heureka.........could you explain how you derived your final formula?

k*x^2 -13*x - 5 = 0

Use the quadratic formula to obtain solutions:  x1 = (13 - sqrt(20*k + 169))/(2k)  and x2 = (13 + sqrt(20*k + 169))/(2k)

Only x1 could be -1/3, so:

(13 - sqrt(20*k + 169))/(2k) = -1/3

3*(13 - sqrt(20*k + 169)) = -2k

39 = 3*sqrt(20k + 169) - 2k

39 + 2k = 3*sqrt(20k + 169)

Square both sides:

39^2 + 4*39*k + 4k^2 = 9*(20k + 169)

4k^2 - 24k = 0

k(k - 6) = 0

k = 0 or k = 6  (Only the k = 6 solution keeps the original equation as a quadratic).

x+y=29/4,

x=29/4-y

find minimum of x+y^2

Let

\(S=x+y^2\\ S=\frac{29}{4}-y+y^2\\ \mbox{This is a concave up parabola so any turning point will be a minimum}\\ \frac{dS}{dy}=-1+2y\\ \mbox{Find turning point }S'=0\\ -1+2y=0\\ 2y=1\\ y= \frac{1}{2}\\ x=\frac{29}{4}-\frac{1}{2}\\ x=\frac{29}{4}-\frac{2}{4}\\ x=\frac{27}{4}\\ \)

\(\mbox{Minimum S} = \frac{27}{4}+(\frac{1}{2})^2\\ \mbox{Minimum S} = \frac{27}{4}+\frac{1}{4}\\ \mbox{Minimum S} = \frac{28}{4}\\ \mbox{Minimum S} = 7\\\)

Here is the graph only y is swapped for x and S is the y axis.

x + y = 29/4  means  y = 29/4 - x

Let f(x) = x + y^2  so f(x) = x + (29/4 - x)^2

Differentiate this with respect to x:   df(x)/dx = 1 - 2(29/4 - x)  or  df(x)/dx = 2x - 27/2

Set this to 0 to find the value of x at which the function is 0:   x_min = 27/4

Put this baxk into the function:   f(27/4) = 27/4 +(29/4 - 27/4)^2  or  f(27/4) = 7

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x^3 + (2a + 1)x^2 + (a^2 + 2a - 1)x + (a^2 - 1) → (a + x + 1)(a + x - 1)(x + 1)

.

arcos or cos^-1

what are the next two numbers? 0,1,4,5,8,?,?

without mistakes:

\(\begin{array}{r|rcll} n &\\ \hline 1& a_1 &=& 0\\ & && & +1 \\ 2& a_2 &=& 1\\ & && & +3 \\ 3& a_3 &=& 4 \\ & && & +1 \\ 4& a_4 &=& 5 \\ & && & +3 \\ 5& a_5 &=& 8 \\ & && & +1 \\ 6& a_6 &=& 9 \\ & && & +3 \\ 7& a_7 &=& 12 \\ & && & +1 \\ 8& a_8 &=& 13 \\ & && & +3 \\ 9& a_9 &=& 16 \\ & && & +1 \\ 10& a_{10} &=& 17 \\ \cdots \end{array} \)

\(\begin{array}{rcll} a_{n}= \left\{ \begin{array}{rl} 2\cdot n-2 \qquad & (\text{n odd})\\ 2\cdot n-3 \qquad & (\text{n even}) \end{array} \right. \end{array}\)

\(\color{red} \boxed{~ \color{black} \begin{array}{rcll} a_n &=& (2\cdot n - 2) -\frac12 [~ 1+(-1)^n ~] \end{array} ~}\)

Solve for x:
x^2-x = 3

Add 1/4 to both sides:
x^2-x+1/4 = 13/4

Write the left hand side as a square:
(x-1/2)^2 = 13/4

Take the square root of both sides:
x-1/2 = sqrt(13)/2 or x-1/2 = -sqrt(13)/2

Add 1/2 to both sides:
x = 1/2+sqrt(13)/2 or x-1/2 = -sqrt(13)/2

Add 1/2 to both sides:
Answer: |  x = 1/2+sqrt(13)/2          or           x = 1/2-sqrt(13)/2

You can use whatever you want for gravity, 10 or 9.8 or 9.81

I'm not sure if I understand your question, m is the mass of the object, v is its velocity and h is what you want to find.

Solve for k:
k x^2-13 x = 5

Add 13 x to both sides:
k x^2 = 13 x+5

Divide both sides by x^2:
Answer: |  k = 13/x+5/x^2

P.S. You cannot get a numerical value for k, because you have 2 unknowns, x and k. You can only solve for k in terms of x.

so 10 would be used as gravity, not 9.8? Also, are m, v, and h all the regular variables for their respective objects?

how many zeros does 100^10 × 10^100 have?

100^10 x 10^100=

10^20 x 10^100 =

=10^120. The product is 1 followed by 120 zeros.

\({K}_{initial} = U_{final} \\ {1 \over 2} {mv²} = mgh\\ h = {1 \over 2} {v² \over g}\\ h = {1 \over 2} {15² \over 10} = 11.25 \ meters\)

2743.6027/6.25 = 438.976432

55

Think again!

\(m = \frac{1}{2} \)

The answer is 8

(9/9)/(2/16)= 8

if ur doing coordinate geometry m=slope