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2 Hints  received. It's not Binary and a number, 12. That's all

4. (Again).......!!!

The central angle formed  by two radial lines draw to each point of intersection of the two circles = 120°.......so.....the arc length, S, of the rest of one of the circles =   2pi(9)(240/360)  = 12pi

So......twice this = the length of the solid line in the figure = 24pi  = about 75.398 cm

No it just went straight to reply :(   Oh well.    ://

Thanks Heureka,     :))

I'll try your reply method now....

If I write nothing more than it means it didn't work.  

Then maybe I will try using Firefox.  :)

the answer is 15 iiiiiiiiiiiiiiiiiiiiiiiii

OK, Alan, thanks......I see that makes sense.....!!!

50*(1-1/1.06^40)/6% + 1000/1.06^40

=849.537.....etc.

Every seat that is sold in the auditorium costs $8.In addition to that, the auditorium makes 300 dollars as a flat rate. If the auditorium made $2772.00, how many seats were sold?

Let the number of seats sold=S

8S + 300 =2,772.00 subtract 300 from both sides,

8S=2,772.00 - 300=2,472.00- divide both sides by 8

S=2,472.00 / 8

S=309 Seats sold.

$100 / 4 =$25.00 each

-7/3v = -42 divide both sides by -7/3

v=-42 / (-7/3)=-42 x -3/7

v=18

Hi Melody,

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I think "concrete" line might refer to the "solid" line, Chris, as opposed to the "dashed" line.

Hello Guest!

what is the required angle for the tan(-1/4)?

The required angle for the tan(-1/4) is arctan(-1/4) = -14.0362°

Greeting asinus :- )  !

Statistical file:
{13, 18, 13, 14, 13, 16, 14, 21, 13}


Average (mean): μ=15
Absolute deviation: 20
Mean deviation: 2.22222222222
Minimum: 13
Maximum: 21
Variance: 7.11111111111
Standard deviation σ=2.66666666667
Corrected sample standard deviation s=2.82842712475
Coefficient of variation cV=0.188561808316
Signal-to-noise ratio SNR=5.3033008589
Median: 14
Mode: 13 - unimodal
Geometric mean: 14.7897264145
Harmonic mean: 14.6050773994
Sum: 135
Sum of absolute values: 135
Average absolute deviation: 2.22222222222
Range: 8
 

http://www.wolframalpha.com/input/?i=15+tosses+of+6-sided+dice,+total+of+53

How does 999! = infinity

999!=4.02387260077093773543702433923 x 10^2,564

I assume this is :

(6x^2-x+10) - (-4+2x^2+8x)     if so........distribute the negative over the terms in the parentheses

6x^2 - x + 10  + 4 - 2x^2 - 8x       combine like terms

4x^2 - 9x + 14

Well 999! is the equivalent to 999*998*997*996*995*... until 1. So it is technically not infinity but multiplying all those number is very difficult for any calculator to do, and it takes to long to process so as far as we are concerned it is infinite.