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Yeah...just didn't know it would be broken that quickly lol

good news for you Heather....the fast has been broken....

Wow, I failed already (I don't practice Ramadan btw). I just ate a sandwich XD

101010101010101010101010101010101010101010101010101010101010101010101010101010101010* 20202020202020202020202020202020202020202020202020202020202020202020202=2.040608e+153

2388.95

10^10^(10 billion)

D. g(x)= 15(0.7)^x

Simplify the following:
(6×49×21 x x (42 x+18))/6

(49 x×21×6 x (42 x+18))/6=6/6×49 x×21 x (42 x+18)=49 x×21 x (42 x+18):
49×21 x x (42 x+18)

Factor 6 out of 42 x+18:
49×21 x x×6 (7 x+3)

49 x×21 x×6 (7 x+3)=49 x^2×21×6 (7 x+3):
49×21×6 x^2 (7 x+3)

49×21 = 1029:
1029×6 x^2 (7 x+3)

1029×6 = 6174:
Answer: |  6174x^2 (7x + 3 )

9n(9y-7n)   there's nothing to "solve," but we can simplify this as :

81ny - 63n²

Solve for n:
(-133)/36=(-2 (4/3-(n)/(3)))/(3)

4/3-(n)/(3)=(4-n)/3:
(-133)/36=(-2)/3 (4-n)/3

3×3 = 9:
(-133)/36=(-2 (4-n))/9

(-133)/36=(-2 (4-n))/9 is equivalent to (-2 (4-n))/9=(-133)/36:
(-2 (4-n))/9=(-133)/36

Multiply both sides of (-2 (4-n))/9=(-133)/36 by -9/2:
(-9 (-2) (4-n))/(2×9)=(-9)/2×(-133)/36

(-9)/2×(-133)/36=(-9 (-133))/(2×36):
(-9 (-2) (4-n))/(2×9)=(-9 (-133))/(2×36)

(-9)/9=(9 (-1))/9=-1:
(-2-1 (4-n))/2=(-9 (-133))/(2×36)

(-2)/2=(2 (-1))/2=-1:
--1 (4-n)=(-9 (-133))/(2×36)

(-1)^2=1:
4-n=(-9 (-133))/(2×36)

The gcd of -9 and 36 is 9, so (-9 (-133))/(2×36)=((9 (-1)) (-133))/(2 (9×4))=9/9×(-(-133))/(2×4)=(-(-133))/(2×4):
4-n=(-133-1)/(2×4)

2×4 = 8:
4-n=(-(-133))/8

-(-133) = 133:
4-n=133/8

Subtract 4 from both sides:
(4-4)-n=133/8-4

4-4=0:
-n=133/8-4

Put 133/8-4 over the common denominator 8. 133/8-4 = 133/8+(8 (-4))/8:
-n=133/8-(4×8)/8

8 (-4) = -32:
-n=133/8+-32/8

133/8-32/8 = (133-32)/8:
-n=(133-32)/8

133-32=101:
-n=101/8

Multiply both sides of -n=101/8 by -1:
(-n)/(-1)=(-101)/8

(-1)/(-1)=1:
Answer: |  n=(-101)/8

A residential home single car garage floor is 8 yds. x 11 ft 8 in. x 4 in. thick. A contractor must use ten (10) #4 ten ft steel rebars (1/2in. X 10 ft) to construct this floor plus the concrete. If delivered concrete costs $200/yd3 and a #4 ten ft steel rebar costs $9.34 (1/2in. X 10 ft), what is the cost of materials in dollars for the floor?

Expressing the dimensions in yds., we have

8yds * 35/9 yds. * 1/9 yds  =   280/81  cubic yds.

So....the total cost =

(280/81) * 200  + 10 * (9.34)  ≈  $ 784.76

23-6 = 17

Mr. Appleton invests $8,800 at 2.8% interest compounded monthly. Find the final amount of his investment after 25 years

FV=8,800 [1 + .028/12]^25*12

FV=8,800[1.002333333]^300

FV=8,800 x 2.012111

FV=$17,706.58

Mr. Appleton invests $8,800 at 2.8% interest compounded monthly. Find the final amount of his investment after 25 years.

The amount, A,  is given by :

A = 8800 ( 1 + .028/12)^(25 * 12)   =  about  $17706.58

 log₅A^x=log₃B  .....we can write

x log₅A  = log₃B   divide both sides by log5A

x =  log₃B /  log₅A

 m^p = t

log_m t = p

7 = 7e0

The parabola y = x^2 is reflected about the x-axis, then translated, so it has a turning point of (-3,5). What is the quadratic equation to represent this parabola?

\(\begin{array}{rcr} x_v &=& -3\\ y_v &=& 5 \end{array} \)

out

Infinity isn't a number, so it doesn't follow the rules of numbers.

Also, infinity comes in various sizes. Therefore, one infinitely large set may be the same size as another infinitely large set; but, then again, one infinitely large set may be larger (or smaller) than another infinitely large set.

Simply 8.04/6.7 = 1.2 acres