How to get exact surface of triangle if i only have hypotenuse and legs.
c=13
a+b=17
I tryed to do it by the system but it is not correct and it can't get correct...
This is a REALLY neat question. I do not remember seeing one like it before.
13 is the length of the hypotenuse.
a and b are the legs.
so using pythagoras's theorem we can say that
\(a^2+b^2=13^2\\ a^2+b^2=169 \qquad (1)\\~\\ \mbox{We also know that }\\ a+b=17\\ \mbox{Squaring both sides we get}\\ a^2+b^2+2ab=289\qquad (2)\\~\\ \mbox{Solve equation 1 and 2 simultaneously}\\ (2)-(1)\\ 2ab=289-169\\ 2ab=120\\ ab=60\\ \frac{1}{2}ab=30\\ \mbox{This is the formula for the area of the triangle so the area is }30units^2 \)
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