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sqrt( 30 ) x sqrt( 10 )  =  sqrt( 30 x 10 )  =  sqrt( 300 )  =  sqrt( 100 ) x sqrt( 3)  =  10 x sqrt( 3 )

-3xy³ + 7xy³ + (-xy³) + (-3xy³)  =        { factor out  xy3 }

xy³  [ -3 + 7 - 1  - 3]   =

xy³ [ 0 ]   =

0

40.8 / 4  =

10.2 meters

y = 2x + 3

-2x + y =  -1      add 2x to both sides of this →    y =  2x - 1

Set the "y's"   equal

2x + 3 =  2x - 1      this has no solution  because we can't add two different quantitiies to 2x  and get the same result...!!!

It is.....make sure you have the calc in RADIAN mode (lower left corner)

x+6.8=12.19

(x+6.8)/2 = 12.19/2

x = 6.095

This sounds as if you are actually supposed to do something, not just get a math answer.

Since  green = 1/3,  blue = 1/6,  red = 1/3,  and the rest is yellow, first figure out how much is in "the rest".

1/3 + 1/6 + 1/3  =  2/6 + 1/6 + 2/6  =  5/6     --->     This means that yellow also equals 1/6.

To run a simulation, you need something that has 6 possibilities. You can use a calculator that has a "random" feature, or just use a regular die.

If you rolled a die, you could mean a result of either 1 or 2 to be green, 3 to be blue, 4 or 5 to be red, and 6 to be yellow.

Then roll the die 30 times, record the 30 results and turn your answers into greens, blues, reds and yellows.

C₂H₈N₂O₄   is  ammonium oxalate   

MW = 12 + 12 + 8 + 14 + 14 + 16 + 16 + 16 + 16 = 124 gm / mole

5.01 x 10^-3 gm  / 124 gm/mole = 4.04  x 10^(-5) moles of ammonium oxalate

There is one ion of oxalate per ammonium oxalate molecule, so the number of oxalate ions

is the same

13.8% = 13.8/100 = .138

Why would you multiply degrees x degrees ?

Hurry plz

Nvm

(3/4)²  =  (3/4) · (3/4)  =  9/16

So:  (3/4)²​ · (34/9)  =  (9/16) · (34/9)  =  34/16  (the nines cancel)

                                                           =  17/8

For problem #2, I'm going to write the cube root of x as x^1/3 ...

So, I believe that g(x) is:  g(x)  =  (x - 2)^1/3 / 2

But, if  f(x)  =  - x³ + 2,

  then  f( g(x) )  =  - [ (x - 2)^1/3 / 2 ] ³ + 2

Simplifying the cube:

                         =  - (x - 2) / 8 + 2

                         =  (-x + 2) / 8 + 2

                         =  (-x + 2) / 8 + 16 / 8

                         =  (-x + 2 + 16) / 8

                         =  (-x + 18) / 8

However, if  f(x)  =  x³ + 2,

  then  f( g(x) )  =  [ (x - 2)^1/3 / 2 ] ³ + 2

Simplifying the cube:

                         =  (x - 2) / 8 + 2

                         =  (x - 2) / 8 + 16 / 8

                         =  (x - 2 + 16) / 8

                         =  (x + 14) / 8

which would match answer (A).

The answer must be 'no', because the result isn't just 'x'.

Does this help?

Also, problem (3) seems to be like problem (1); can you follow the steps of problem (1) to finish problem (3)?

Cant hold us maklamore+Ryan Lewis but math only pleaese

Math only thank you

We are sorry to say but this is for math only pleaese and thank you

5y-3/5=4/5 first add 3/5 to both sides

5y=4/5+3/5 simplify

5y=7/5 divide both sides by 5

y=7/5/5 simplify

y=7/25

Factor the following:
x^3-5 x^2-x y^2+5 y^2

Factor terms by grouping. x^3-5 x^2-x y^2+5 y^2 = (5 y^2-x y^2)+(x^3-5 x^2) = x^2 (x-5)-y^2 (x-5):
x^2 (x-5)-y^2 (x-5)

Factor x-5 from x^2 (x-5)-y^2 (x-5):
(x-5) (x^2-y^2)

Factor the difference of two squares. x^2-y^2 = (x-y) (x+y):
Answer: |(x-y) (x+y) (x - 5)

x³ - 5x² - xy² + 5y²

When you grouped them you got:

x³ - xy² - 5x² + 5y²

Now, when you factor out the minus sign from the last two terms, you should get:

x³ - xy² - (5x² - 5y²)      <---  Notice the minus sign in from of the 5y² term (because the minus was factored out)

Continuing:

x(x² - y²) - 5(x² - y²)

(x² - y²)(x - 5)

(x + y)(x - y)(x - 5)

you just did :p

I don't get the other problems..

Yeah that's what i'm trying to use

I'll answer the first part; but I have two questions.

1)  Are you using * to represent the composition of functions? Usually * asterisk) is used to indicate the multiplication of          functions and º (a small circle) is used to represent the composition of functions.

2)  I believe that the original problem has fractions as follows:

     f(x)  =  (2x + 3) / (4x - 3)

     g(x)  =  (3x + 3) / (4x - 2)

Are  f(x)  and  g(x)  inverse functions.

This can be solved in two ways:

1)  Find the inverse of  f(x)  and see whether or not it equals g(x).

2)  Find out if  f( g(x) )  =  g( f(x) )  =  x

By the nature of the answers, I believe that the assignment was to use procedure #2.

(f º g)(x)  =  f( g(x) )  =  [ 2 · g(x) + 3 ] / [ 4 · g(x) - 3 ]

                                 =  [ 2 · (3x + 3) / (4x - 2) + 3 ] / [ 4 · (3x + 3) / (4x - 2) - 3 ]

                                 =  [ (6x + 6) / (4x - 2) + 3 ] / [ (12x + 12) / (4x - 2) - 3 ] 

Multiply both the numerator and the denominator by  (4x - 2)  and simplify:

                                 =  [ (6x + 6) + 3(4x - 2) ] / [ (12x + 12) - 3(4x - 2) ]

                                 =  [ 6x + 6 + 12x - 6 ] / [ 12x + 12 - 12x + 6 ]

                                 =  [ 18x ] / [ 18 ]

                                 =  x

I'll let you show that  (g º f)(x)  =  x  also.

This shows that the answer to problem 1 is 'yes'.

You can use this procedure with the other problems.

2/3 = -.8 x    Divide both sides of the equation by -0.8

(2/3) / -0.8 = x

(2/3) / (-8/10) = x

2/3  x (-10/8) = x

-20/24 = -5/6 = x