Questions   
Sort: 
 #2
avatar
0
Sep 30, 2016
 #1
avatar
0
Sep 30, 2016
 #1
avatar
0
Sep 30, 2016
 #3
avatar
0
Sep 30, 2016
 #1
avatar
0
Sep 30, 2016
 #1
avatar
0
Sep 30, 2016
 #9
avatar+2432 
+6

Someone is mixing up the metaphors here.

 

It’s not “my formula” that I played with for hours. That formula popped out like an oversized “Where’s Wally” character. Heureaka probably didn’t mention it because that would be like saying, “Notice the big elephant in the room.” 

 

What I played with for hours was the formula of “little mice” waltzing in the shadows.  This one: G_n(a_n)(z) = (z (-z^3+4 z^2-6 z+4))/(z-1)^4.  The Rube Goldberg formula (but only if it works). 

 

I do not know how to make these series (0, 1, 4, 10, 20, 35) or (0, 4, 10, 20, 35) appear when [n=0, 1, 2, 3, 4, 5, . . . ] probably because I do not know how to do [nested sub-scripted indexes??] Gn(an)(z)=Rube Goldberg formula.  I’m assuming the formula works but is poorly explained – z cannot = 1 else there is a division by zero.

 

By using the formula provided by "Guest #4", "from one of Hade’s rivers: G_n(a_n)(z) = (z (-z^3+4 z^2-6 z+4))/(z-1)^4", I derive the 35th term of the this series as: 7,140!!!!!. I tried a couples more terms for both.

 

This is great! Instead of just saying you did it, can you show an explicit example? step by step in time.  Remember a waltz is in ¾ time not 35

 

We genetically enhanced chimps are happy to learn from choreographed, waltzing mice, plucked, along with the formula, from one of Hade’s rivers –even if they do step a little out of time, but if they are just running around looking for the big cheese, we’re going to snack on them.  Right now, they are looking very tasty.

Sep 30, 2016

8 Online Users

avatar
avatar
avatar
avatar
avatar
avatar