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Still....infinity.

Let Player1 = x

Player2       = 2x    (he scored twice as many points as player1)

Player3       = 2x+10  (because player2 scored 10 points less than him)

x  +  2x   +  2x+10  = 70 points

5x + 10 =70

5x = 60

x = 12     Player2 = 24   Player3=34

This is quite a doozer!!. There is a formula to solve this type of financial problem, but before giving the answer, I will let all the answerers on this forum to take a kick at the can!!. Here is the formula:

100,000=550.1 * {(((1+g)/(1.005))^120 - 1) / (g - .005)}, solve for g.

You are given that                                       (x + y + z)(xy + xz + yz)  =  25

Expanding the left side of                            (x + y + z)(xy + xz + yz) =  25 

you get:                            x²y + x²z + y²x + y²z  + z²x + z²y + 3xyz  =  25

Factoring this, you get:         x²(y + z) + y²(x + z) + z²(x + y) + 3xy  =  25  

Since you know that             x²(y + z) + y²(x + z) + z²(x + y)              =  7

Subtracting down:                                                                         3xyz  =  18

Dividing by 3:                                                                                   xyz  =  6

x has no value, so all we can do is simplify.

Add 8x to both sides.

-8x+2y=20

+8x       +8x

You now have 2y=8x+20

Divide both sides by 2 and remember to divide EVERY TERM by 2.

2y=8x+20

 2       2

You now have y=4x+10

So, your answer is y=4x+10

Hope this helped!

12-5 = 7

7

p=1 1/2 , q=3

So you've gone 120 miles, and the total trip is 360 miles, so you've gone 120/360 of the trip.

You can simplify this fraction by dividing the top and the bottom of the fraction by common factors.

I can see that 10 is a common factor, so:

120/360 = (120/10)/(360/10) = 12/36

I can see that 12 is a common factor, so:

12/36 = (12/12)/(36/12) = 1/3

If you START with a full tank  you can go 264 miles before your FIRST stop

second stop @ 528

third                   792

 fourth               1056

 fifth                   1320

  sixth                 1584

 seventh              1848     which will carry you all of the way to 2112, so you will need no more stops for gas.

Answer :  7 gas stops

28+(9*6-23)*4^0  =      evaluate within the parentheses, first

28 + (54 - 23)*4^0  =  

28 + ( 31)*4^0      =         exponentiation is done next...remember that a^0  = 1   as long as  "a" ≠  0

28 + (31)* 1  =

28 + 31   = 

59

You can travel  12 x 22 =  264 miles on a tankful of gas....so  you will have to stop and fill up

2100 / 264 =  7.954   times  =  8  times

98  =  14 x 7   =  2 x 7 x 7   =   2 x 7²

Consider two infinite geometric series. The first has leading term a, common ratio b, and sum S. The second has a leading term b, common ratio a, and sum S. Find the value of a+b. 

We have that

a / [ 1 - b]  = S       and b / [ 1 - a] =  S

Therefore

a / [ 1 - b ]  =  b / [ 1 - a]      cross-multiply

a [ 1 - a]    =   b [ 1 - b]    simplify

a - a^2   = b - b^2    rearrange

( a - b ) =   a^2 - b^2   factor the right side

(a - b) =  (a - b) ( a + b)         divide both sides by  (a - b)

1  =  a + b

0.24

|2y-3|=29 

(1).  2 y > 3

       2y - 3 = 29

        2y = 32

        y = 16

(2).  2y < 3

       3 - 2y = 29 

       -2y = 26

         y = -13

.

Correct!