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Do you work for the NSA???!!

THERE ARE NO SOLUTIONS THE WAY YOU HAVE WRITTEN THEM!!!!. Why? Because the three numbers that add to 350 cannot be multiplied by 0.66 that will add to 3025!!!. Take these 3 numbers:

110 + 116 + 124 = 350. Then: 110*.66 + 116*0.66 + 124*0.66 =231, which is a far cry from 3,025!.

If you changed this 0.66x +0.66y +0.66z = 3025 from additions to multiplications, then you can get some solutions.

Multiply the bases and add the exponents. It's 15*10^13

|-3| = 3

7-3 = 4

If you're 2 and your sister is half your age, there is one year difference between you (You are older by 1 year). If you're 100, your sister is 100-1 or 99.

Divide both sides by 1500000

(1-c)^8 = 1/15

Take the eighth root

1-c = sqrt(1/15, 8)

Subtract 1

-c = sqrt(1/15, 8) - 1

Multiply by -1

c = 1 - sqrt(1/15, 8)

184 loaves in four hours/4 hours = 46 loaves in one hour

You are right. It is NOT zero but a very small number. The reason why the calculator you are using is displaying it as zero, is because it is not ACCURATE enough to display very small or very large numbers. But, there are other calculators that will display very small and very large numbers:

1.92^-1,111 =1.7878657732222884799242370868693 x 10^-315.

use the formula V*t=x so if the velocity is 8 2/3 miles per hour and you need to travel 5 1/5 miles then (8 2/3)*t=5 1/5,

so t=(5 1/5)/(8 2/3)= .6 hours

it's 35/100   0r  0.35

4 out of 5  is 4/5 = 80%

80% of dentists recommend this gum

80% x 185 =  80/100 x 185 = 148 of them would recommend the gum.

Another way     4/5 recommend the gum   4/5 x 185 = 148

Area of a circle = pi x r^2

68.87 cm^2 = pi x r^2

68.87/3.14159=r^2

21.922=r^2

4.68 cm = r

Understand what a percent means. It's just one hundredth of something.

So 70 per cent is 70 hundredths  or 70/100 if you write it in math speak.

So 70 per cent of 250 is just  70/100       x       250.    I'm sure you can do the last bit. 

13 percent of 40   = 13/100    x 40

17 percent  of 92  =  17/100  x 92         etc     etc    etc         Not difficult.

Sometimes people get confused if they are asked a percentage of another percentage. Method  is just the same.    5 percent  of 18 percent   is 5/100   x  18/100.           

No,we are different guests,but essentially we have both given you the same method/idea using the 'u substitution' and integration by parts..(I put the first reply on.)   The Reduction Formula method is just an adapation of integration by parts. Good luck.

2^(-4) is 1/16, not 16.

.

Ilya and Dan shared 360 hats in the ratio 7:5. How many more hats did Ilya have than Dan?

Ilya's share of the hats =7 / (7+5) x 360 =210 hats.

Dan's share of the hats = 5 / (7+5) x 360 =150 hats

210 - 150 =60 more hats that Ilya has than Dan

x=-4 or x=4

Try this online calculator and see if it helps you in solving your Integral:

http://www.integral-calculator.com/

Thanks very much.  :)

Are you the same guest or 3 different guests?

Anyway I'll take a proper look in the morning. 

I don't know the reduction formula but maybe I can follow the rest://

\({2}^{2}x+256+\frac{1}{2}\)

\(4x+256+\frac{1}{2}\)

\(4x+\frac{512}{2}+\frac{1}{2}\)

\(4x+\frac{513}{2}\)

\(4x+256.5\)

I think this might mean:   

2^x = 256^(1/2)

in which case:

2^x = 16

x = 4

.

Here is your solution step-by-step in non-LaTex everyday language!.

Take the integral:
 integral sec^3(x) dx

Use the reduction formula, integral sec^m(x) dx = (sin(x) sec^(m-1)(x))/(m-1) + (m-2)/(m-1) integral sec^(-2+m)(x) dx, where m = 3:
 = 1/2 tan(x) sec(x)+1/2 integral sec(x) dx

Multiply numerator and denominator of sec(x) by tan(x)+sec(x):
 = 1/2 tan(x) sec(x)+1/2 integral(sec^2(x)+tan(x) sec(x))/(tan(x)+sec(x)) dx

For the integrand (sec^2(x)+tan(x) sec(x))/(tan(x)+sec(x)), substitute u = tan(x)+sec(x) and du = (sec^2(x)+tan(x) sec(x)) dx:
 = 1/2 tan(x) sec(x)+1/2 integral1/u du

The integral of 1/u is log(u):
 = (log(u))/2+1/2 tan(x) sec(x)+constant

Substitute back for u = tan(x)+sec(x):
 = 1/2 tan(x) sec(x)+1/2 log(tan(x)+sec(x))+constant

Factor the answer a different way:
 = 1/2 (tan(x) sec(x)+log(tan(x)+sec(x)))+constant
Which is equivalent for restricted x values to:

Answer: |= 1/2 (tan(x) sec(x)-log(cos(x/2)-sin(x/2))+log(sin(x/2)+cos(x/2)))+constant

Expand the following:
16×14×9 (x-3) (5-x)

16×14 = 224:
224×9 (x-3) (5-x)

224×9 = 2016:
2016 (x-3) (5-x)

(x-3) (5-x) = (x) (5) + (x) (-x) + (-3) (5) + (-3) (-x) = 5 x-x^2-15+3 x = -x^2+8 x-15:
2016 -x^2+8 x-15

2016 (-x^2+8 x-15) = 2016 (-x^2)+2016 (8 x)+2016 (-15):
-2016 x^2+2016 8 x-15 2016

2016 (-15) = -30240:
-2016 x^2+2016 8 x+-30240

2016×8 = 16128:
Answer: |-2016 x^2+16128 x-30240

substitute   u = tan^2(x)      so du = -2tan(x)sec^2(x)dx     (chain rule and quotient rules for differentiation used here)

and use the the identity  sec^2(x) =  1 + tan^2(x) so you want to integrate

sec(x){1+tan^2(x)} dx          using sec^3(x)  = sec(x) {1+tan^2(x)}

From the u  - substitution,  sec(x) = sqrt(1+u)       , 1+ tan^2(x)=  (1 + u)  and

dx= -du/2tan(x)sec^2(x) = -du/2sqrt(u)(1+u).

If you now set up this integral you should get the integral of

-1/2(sqrt(1+u)/u du  which you can now integrate by parts.