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4)

3^(8-6+2)*5*7=945

distribute

3x+3=15

    -3  -3

3x/3=12/3

x=4

It is 0.8097840332...

tan(39)=0.809784033195

3/5 x 2/4 x 1/3

simplify the 2/4 to 1/2

3 x 1 x 1=3

5 x 4x 3=60

3/5 x 1/2 x 1.3=3/60=1/20

That is a lot of work.

When you need to DIVIDE by a fraction, flip it over and MULTIPLY

-9/16   /   3/4    =  -9/16  x  4/3  = -36/48    then simplify      -3/4

Use the distributive property to multiply through then collect like terms

2a - 6 + 4b -2a+2b +6 +5

2a-2a  +4b+2b  -6+6+5

6b+5

The antilog function is just the  10^x   key right next to the log key

1. Find the three other angles of parallelogram ABCD if ∠ A is equal to:
    a. 75 degrees   b. 62 degrees  c. 95 degrees  d. 82  1/2 degrees

y=mx+b     substitute in one of your pints to find 'b'    .....  as a check see if the other point is answered by the resulting equation.....

Angle Side Angle postulate.  See http://www.mathwarehouse.com/geometry/congruent_triangles/angle-side-angle-postulate.php for details.

How did you get that .7?

you got his question from cellcraft, didnt you?

|x - 2| - 4|-6|

|x - 2| - 4*|-6|

=|x - 2| - 4* 6

=|x - 2| - 24

       if 

        x-2>=0 then x>= 2 and

=x-2-24

=x-26

     if

       x-2<0 then  x<2   and

=2-x-24

=-x-22

so

If x>=2 then the expression will equal   x-26

and

If  x<2 then the expression will equal    -x-22

5(-3x - 2)       - (x - 3) =    -4(4x + 5)    + 13

-15x - 10       - 1(x - 3) =    -4(4x + 5)    + 13

-15x - 10       - 1x + 3 =     -16x   -20    + 13

-16x - 7                      =     -16x   -7   

both sides are the same so this equation is true for all real values of x.    :)

I just entered this into google search engine and the answer came up straight away.

"ASA postulate?"

 In parallelogram ABCD, if ∠B = (x-9)°, and ∠A=(2x+29)°, find ∠C and ∠D

Hi Yukikawa :)

Start by drawing a paralelllogram on a bit of paper.

opp angles in a paralellogram are congruent (ths same) so 

<C=2x+29    and  <D= x-9

also all the angles add up to 360 degrees.  So you can add them all up and solve the equation to get the value of x

then

plug the value of x into <c and <D to get the actual numerical value for them.

You try it on your own.

If you post your answer I'll check it for you :)

Do you want the area of the perimeter?

Either way you do not need to remember more formula!

Area of a circle is  \(\pi r^2\)

If the angle at the of the sector is  \(\theta ^\circ\)

(note this theta is in degrees)

then you will have      \(\frac{\theta}{360}\;\; \text {of the circle}\)

So the area will be     ​\(\frac{\theta}{360}\;\;\pi r^2\;\;\;units ^2\)​

----------------------------------------------------------------

Similarly the circumferenc of a circle is   2*pi*r

So the perimeter of the sector will be 

\(Perimeter=\frac{\theta}{360}\;*2\pi r + \text {the two straight edges}\\ Perimeter=\frac{\theta \pi r}{180}\; + 2r\qquad units\)

123876/34/2/8=

123876/34        /2/8=

\(\frac{123876}{34}\div        2\div8=\\ =\frac{123876}{34}\div       \frac{ 2}{1}\quad\div\frac{8}{1}\\ =\frac{123876}{34}\times       \frac{ 1}{2}\quad\div\frac{8}{1}\\ =\frac{123876}{34*2}     \quad\div\frac{8}{1}\\ =\frac{123876}{34*2*8}   \\ =\frac{123876}{34*2*8}   \\ \)

You can finish it :)

The difference between Melody's and DarkStrider's answer is:

Melody has interpreted the expression as  ln[(1+x)^-1]

DarkStrider has interpreted it as    [ln(1+x)]^-1

Different expressions give different results!

Only the (1+x) is raised to the -1

IT IS NOT      (ln(1+x))^-1

What is the magic word? I think, please.

6(5x-3y)-4y(2x-1)+5xy-2(x-7y)=

30x-18y-8xy+4y+5xy-2x+14xy=

28x+11xy-14y

Take ln(1+x) as t.

Find dt in terms of dx.

Replace dx with (1+x)dt.

Solve for d/dt of transformed expression.

The answer is: -[ln(1+x)]^-2 / (1+x)