Sorry Tony!. I only have ONE solution for you!.
Solve for x:
x/(x - 3) = (2 x)/(x + 6)
Cross multiply:
x (x + 6) = 2 x (x - 3)
Expand out terms of the left hand side:
x^2 + 6 x = 2 x (x - 3)
Expand out terms of the right hand side:
x^2 + 6 x = 2 x^2 - 6 x
Subtract 2 x^2 - 6 x from both sides:
12 x - x^2 = 0
Factor x and constant terms from the left hand side:
-(x (x - 12)) = 0
Multiply both sides by -1:
x (x - 12) = 0
Split into two equations:
x - 12 = 0 or x = 0
Add 12 to both sides:
Answer: |x = 12 or x = 0