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You don't have enough information. You need growth rate/year and maybe endpoint year of growth to get the yearly lbs. of CO2 and assume the immature tree is 0 year, avg.growth/year i.e it is an exponential function like interest compounded starting with $26 and when will it reach $396 at  x% interest /yr constant growth. Otherwise, you are saying a certain mature tree will take in 26 lbs., how many years before it will have taken in 396 lbs. or 396/26.

2 and if you do not know that you are an idiot

What is sqrt3(sqrt3(csc(cosh(sqrt3(sqrt(sec(csc(sqrt3(sqrt3(549)5586^3)68255)6)265414256+553)55^3))))^3452^34524)

if you can get you just saved my life literally😉🤓

Check the Desmos graph : https://www.desmos.com/calculator/mlfl2icxyf

It appears that this will be true when  x >  0

h + 4  = 5b         write 5b  as  5b / 1

  d

h + 4    =   5b         and note the interesting property that we can "flip"  both fractions

   d             1

  d      =     1        multiply both sides  by h + 4

h + 4        5b

d   =     h + 4

              5b

390#  /  26# / yr   =  390/26  yr = 15 yrs

I think the formula you need  is:

A = P( i (1+i)^n / ((1+i)^n-1)    A = monthly payment   n = 12 payments   i = periodic interest in decimal = 19.5/12=.01625

A= 6927 (.01625 (1.01625)^12/  (1.01625)^12  -1)

A=640.02    each month for 12 months

Hi, Melody

my graphing calculator is

Disregard  my answer.....I think EP is on the right track......!!!.....I didn't read the word "than"

- .52x  + .32 x = 4.6

-.2x = 4.6

x = 4.6/(-.2)

x = - 23

...or maybe it is this:

(7+2x)   - 1/4x                   1/4 x less than the sum

7 +2x - 1/4x

7 + 1 3/4 x

or maybe you meant

1/4x < (7+2x)   Subtract 2x from both sides

-3 3/4 x <7        Divide both sides by - 3 3/4 (NOTE: this will REVERSE the < sign to > )

x > 7 / (3  3/4)

x > 28/15

x> 1  13/15

(5-x)+(5+x)=0  simplify

5 + 5 + x  - x  = 0

10  = 0       which is impossible.....therefore.....no solution.....

I assume that we have :

(1/4)x  - [7 + 2x}   simplify

(1/4)x  - 7  - 2x          combine like terms

(1/4)x  -2x  - 7            [  2x  =  (8/4)x ]

(1/4)x - (8/4)x  - 7  =

-(7/4)x   - 7

840 sq miles

There are  [ 5280^2]  ft. in one square mile....so

840 * 5280^2   =  23,417,856,000    sq. ft.

hiz

8x - 3y ≤  -12

Let's   get a couple of solutions to this equation, first

8x  - 3y  = -12

Let x  =0      so  ... 8(0)  -3y  = -12  →  -3y = -12  →  y  =4    so we have the point  (0,4)

Now...let y  = 0     and we have    8x - 3(0)  = -12   →   8x  = -12   [divide both sides by 8]   →     x  = -12/8  = -3/2

So....we have the second point,   (-3/2 , 0)

Plot these points on a graph   and draw a  solid line through them  [ implied by the  "  ≤ "  ]

Now.......pick a point on either side of the line  - I'll choose (0,0)  -    and put it in the original equation....if this point makes the equation true.....shade  the side of the line that includes (0,0)....if  (0,0)  malkes the original equation false.....shade the other side of the line....so

Testing (0,0)  we have

8(0)  - 3(0)   ≤  -12    ???

0  ≤  -12   ???

This is false....so shade the other side

Your graph should look like this :   https://www.desmos.com/calculator/we4cvh0v41

Note that (0,0)  is not include in the solution area  !!!!

It depends on what type of answer you want if you want the correct answer it is 8.8163265306122449 or round it to 8.8

Or are did you make a mistake and mean 49/432 and that is 0.1134259259259259 then round it to 0.11

I think that the answer is much larger.......

See the pic below....it represents a cross-section of the sphere.....for our puposes....we'll set the radius of the sphere at R 

The cut is made at DE with the radius of the cut = CD  = .25R  thus ...the circumference of the slice is 1/4 that of the circumference of the whole sphere

The  "formula"  for the volme of a spherical cap  is  [ pi * H^2 * (3R - H)] / 3

Where H  is the height of the cap =  the distance measured along the x axis between "C" and the  right edge of the circle  = R (1 - √15/4) .........

And the voliume of the cap  [ with a little computational help from WolframAlpha ]  is :

[((2 π)/3 - (11 sqrt(15) π)/64) R^3]

And the volume of the entire sphere   is just  (4/3) * pi * (R)^3   

So......taking the ratio  of   weights to volumes......the  weight of the whole cheese, W, is given by

W/ 5   = [ (4/3)piR^3] / [((2 π)/3 - (11 sqrt(15) π)/64) R^3]       solve for W

W =  5 * [ (4/3)piR^3] /    [((2 π)/3 - (11 sqrt(15) π)/64) R^3]  ≈   6682.34  lbs.

As Melody often says ; "That is what I think....."

69 to third power times three

79% or a C

(2³)³ or 2⁹ = 512

512

1/2

I AM SWAG 

3/10 or 0.3