\(5/12-1/6=5/12-2/12=(5-2)/12=3/12=0.25\)
\((-63/3) + 1 = -21+1= -20\)
1300*15.25/100+1300=5993/4=1498.25
5/12-1/6=30/72-12/72=18/72=9/36=3/12=1/4=0.25
45555000*5756=262214580000
I am a civil engineer. It's very easy.
Correction: I'd like to see the GIANT fox that can eat a DEER in THREE HOURS !!!!
BTW.....I'd like to see the GIANT fox that can eat a DEER in TWO HOURS !!!!
9 m 10cm = 9.1 m (there are 100 cm in a meter)
9.1m / 65 m x100% = 14%
No. When you run in to questions like this, it is often helpful to substitute some numbers in there to see
Let's let x = 4
2*3^4 = 6^4 ?????
162 = 1296 No! so 2*3^x does NOT equal 6^x
One deer = dr
Tiger rate = 1 dr/ 2hr
Fox rate = 1dr/ 3hr
Wolf rate = 1 dr/6hr
To eat 1 dr how long ?
1 dr / (1dr/2hr + 1dr/3hr + 1dr/6hr) = 1/(1/2+1/3+1/6) = 1/(6/6) = 1Hour
Another method: Using Amnesia's nice picture , you can see that the now divided triangle has angles of 30 60 90
Use law of sines sin60/b = sin 30/10 ('10' comes from dividing one '20' side in half = 10)
solve for b = 17.3205
Hey Melof=dy.... No offense was taken......that is a problem with texts....they lack tone and volume: hard to tell what someone intends at times. I was glad they answered my f/u Q ! G'Day !
Just keep pressing the square root button \(\sqrt x\) fourth row, fourth column.
.
Replace R by x and the calculator on the home page solves it:
Input:
Press Enter to get:
APY =Annual Percentage Yield = Annual Effective Rate.
what is 29.9/100 * 125
Both operators are point calculations. Equal. Move from left to right.
\(29.9 / 100 \times 125\)
\(\large =\frac{29.9}{100}\times 125=0.299\times 125=37.375\)
!
It is still infinity$
But no one is THAT rich ://
Tiggsy didn't mean any offense EP.
He was just being helpful.
just hit the 2nd button
what is the apy at 15% compouned semianually
I do not know what apy stands for but
The annual effective interest rate is
\((1+0.075)^2-1\\ =1.075^2-1\\ =1.155625-1\\ =0.155625\\ =15.56\%\)
Nice pic amnesia :))
Thanks Alan,
I'd still be interested in someone doing it properly though. :/
Maybe my answer really is fully acceptable - I am not sure.
e^(π.i) - 1 = 0. How does this most famous equation in Math =0? Thanks for help.
\(\boxed{e^{i\theta}=cos\theta+isin\theta}\\ \)
\(e^{\pi i}\\=cos\pi+isin\pi\\=-1+i*0\\ =-1+0\\ =-1\\ so\\ e^{i\theta}{\color{red} +}1=0\)
!
