We first place the non-math books. There are 4 choices for the first book, 3 choices for the second book, 2 choices for the third book, and 1 choice for the last book. Then we have to put the two math books between the four non-math books such that there is at least one non-math book between the two math books. We see there is a total of 5 openings created by the four non-math books. So the first math book has 5 choices, and the second math book has 4 choices.
So the total number of ways the books can be placed is 4*3*2*1*5*4 = 480