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Answer here :  http://web2.0calc.com/questions/help-asap_24787

[24]r^2 = 3rd term

[ 32 / 3]r^4  = 5th term    .......so.....

24(r)^2  = 32/3    rearrange

 r^2    =  [32 / 3] / 24

r^2  = 32/72

r^2  = 4/9

r = 2/3

And the first term  =   24(3/2)^2  = 54

So... the 10th term  =  54(2/3)^9  =  1024 / 729

Thank you!

1. Distance beween (−4,1) and (−1,−2)  = √ [( −4 − −1)^2  + ( −2 − 1)^2 ]  = √[ 9 + 9] = 3√2

    Distance beween (−4,1) and (−6,−1)  = √ [( −4 − −6)^2  + ( −1 − 1)^2 ]  = √[ 4 + 4] = 2√2

Area =  3√2 * 2√2  =  6√4  = 6 * 2  = 12  units^2 

The formula for the monthly payment that you have is slightly wrong:

P = PV. R.{[1 + R]^N/ [1 + R]^N - 1}

P =12,000 x 0.03{[1 + 0.03]^24 / [1 + 0.03]^24 - 1}

P = 360 x { 2.032794 / 1.032794}

P = 360 x          1.968247...

P =$708.57 - The monthly payment!.

P.S. Your monthly interest rate of 3% per month is very, very high!!. It is of course 36% annual rate, compounded monthly!!!. Make sure that the 3% per month is accurate.

2. What is the value of x?

[180  − 52 ] / 2  = 64“  = a base angle of the triangle on the left

180 − 64  = 116°   supplemental  angle to this base angle

[180 − 116] / 2  =  x  =  32°

3.   [9x + 2]  = [2x + 4] + [6x + 6 ]     [exterior angle theorem]

9x + 2  = 8x + 10 

x = 8

So.....m < PQS  = 9(8) + 2  = 74°

P. S.  ...   I'll solve the first one in a bit

And your second point was....????

Anyone?

These represent the sum of the first n positive integers

The "foumula"  for the nth term is   [ n ( n + 1) ]  / 2

(2)  -triangle EDC is triangle ABC rotated clockwise 180dg about point C

      -Triangle ABC is triangle EDC reflected across the y axis and reflected across the x axis

0.0043 x 10^9   = 4300000/ [12 *5280 ]  = 67.87  miles

(1) reflect across y=3

     rotate counterclockwise 90 degrees around the origin

\(-\frac{1}{3}(b)=9 \)

divide by -1/3=

\(b=\frac{9}{-\frac{1}{3}}\)

simplfiy=

b= - 27

x - 3y = 1     →    x = 1 + 3y      (1)

3x - 5y= 11     (2)

Sub ( 1)  into (2)

3 ( 1 + 3y ) - 5y= 11

3 + 9y  - 5y = 11

3 + 4y  = 11       subtract 3 from both sides

4y  = 8               divide by 4

y = 2

And

x = 1 + 3y 

x = 1 +  3(2)  =  1 + 6  = 7

(x , y )  = (–1/√2,  1/√2 )

2*8=16