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if you have drived in 2 hours and 50min and you have drived 60km what is youre medium driving speed?

\(\large v=\frac{s}{t}=\frac{60km}{(2+\frac{50}{60})h}=\frac{60km}{2.83\overline3h}=\color{blue}21.176\ km/h\)

  !

what's zero divided by zero?

No can do   

(x+3)^2 = (x+3)(x+3) = x ^2 + 3x + 3x + 9 =  x^2 + 6x + 9

- sqrt(2) =  - 1.414213562373095

sqrt(-2) =     1.414213562373095  i        Where i = \(\sqrt{-1}\)

The ' 2nd ' button  (upper left)    is the 'shift ' button on Web2.0 calc

1 / (a+b)^-1 =  (a+b)

73.5% as a fraction is   735/1000 =147/200 = 0.735

f (x) = 4x^3 + 2x + 1, g (x) = x^5 - x^3 +2 and h (x) = 2sin (x)

1.  ( f + g)x =  x^5 + 4x^3 - x^3 + 2x + 3 .......  domain is (  -inf, + inf)

4.  ( f * g) x  =  4 x^8 - 2 x^6 + x^5 - 2 x^4 + 7 x^3 + 4 x + 2   ..... domain is (  -inf, + inf)

h=-T[dv/dp]p

Solve the separable equation h = -p T(( dv(p))/( dp)):
Solve for ( dv(p))/( dp):
( dv(p))/( dp) = T^(-1) (-h/p)
Integrate both sides with respect to p:
Answer: |v(p) = integral T^(-1) (-h/p) dp = integral T^(-1) (-h/p) dp + c_1, where c_1 is an arbitrary constant.

2 hrs 50 min   =   2 + 5/6 hrs  =  17 / 6 hrs

So

D / T   = R

60 km / [17/6] hrs  =

60 * 6 / 17  km/hr   ≈  21.18 km / hr

if you have drived in 2 hours and 50min and you have drived 60km what is youre medium driving speed?

2 hours + 50/60 =2 5/6 hours =17/6 hours.

60 / (17/6) = 60 x 6/17 =360/17 =21 3/17 km/h - the average speed.

The formula for cosine is this, cos= The adjacent side over the hypotenuse side. or cos=a/h

1,3,9,27 what is the pattern,the next 2 numbers?

1, 3, 9, 27, 81, 243......... Multiply each term by the common ratio of 3.

when we have the coordinates of two points, and that we want to calculate the distance between them, we do the following: 

1-calculate the victor that links the two points ( in this case MZ )

2-we calcutate the magnitude of the vector MZ 

\(MZ= \begin{pmatrix} -1-6\\ 14-16 \end{pmatrix} = \begin{pmatrix} -7\\ -2 \end{pmatrix}\) this is the vector MZ 

Now its magnitude:

\(MZ = \sqrt{(-7)²+(-2)²}=\sqrt{53} = 7.2801..=7.3\)

d = √ [ -1 - 6)^2  + ( 16 - 14 )^2 ]  =  √ [ ( - 7)^2  + ( 2 )^2 ]  = √  [49 + 4] = √ 53  ≈  7.3

A supplier sells 214214 pounds of mulch for every 113113 pounds of gravel. The supplier sells 172 pounds of mulch and gravel combined. How many pounds of each item does the supplier sell?

43 mins ago

Mulch   =  172 [ 214214] / [ 214214 + 113113]  ≈  112.6 lbs

Gravel  = 172 [ 113113] / [ 214214 + 113113]  ≈ 59.4  lbs

Midpoint  =  (  [ add x's] / 2 ,   [add y's] / 2  )   .....so we have

x value of midpoint  = [ 3 +  x] / 2  = 5       multiply both sides by  2

                                   3 + x  = 10      →   x = 7   

y value of midpoint  = [ 5 +  y ] / 2  = - 11       multiply both sides by  2

                                   5 + y  = - 22          subtract  5 from both sides

                                        y   =   - 27

Midpoint =   ( 7, - 27)

3^(9) = 19 683     divide both sides  by  3

3^9 / 3   = 19 893 / 3

3^8 / 3^1  =   6631       .... using  a^n / a^m   =  a^[n - m]    

3^ [9 - 1]  = 6631

3^8  = 6631

2x-x-7=31  combine like terns

x - 7   = 31     add 7 to both sides

x = 38

A supplier sells 214214 pounds of mulch for every 113113 pounds of gravel. The supplier sells 172 pounds of mulch and gravel combined. How many pounds of each item does the supplier sell?

9625 = 5^n * 7 * 11

9625 = 5^n * 77      divide both sides by 77

125 = 5^n          [125  =5^3 ]

5^3  =  5^n       which implies that  n = 3

2 x ^2 + 38 x + 180 = 0       divide through by 2

x^2 + 19x + 90 = 0   .... factor.....

(x  + 9) ( x + 10)  = 0

Set each factor to 0  and  x = - 9   or x = - 10

9625 = 5^3 * 7 * 11

n = 3