You realize there is a calculator on this websit that will do this for you ......don't you?
650000*(1.04)^7 = 855355.656503296 Straight from the calculator......just sayin'
See other (same) post
vf = vo + at
vf = 200m/s + 18.2 m/s^2 x 15 sec = 473 m/s final velocity (north)
0.000000000000000000000102 = 1.02 * 10 -22
V =W * L * H
20 = 5 * √3 * H divide both sides by 5 *√3
20 / [ 5 * √3 ] = H ≈ 2.31 units
If each shirt requires 2.33 yards/shirt and you need to make 26 shirts :
2.33 yd/shirt x 26 shirt = 60.58 yd (see how the 'shirt' dimension 'cancels out' ?)
81 cupcakes is to 37.5 % as x is to 100% ......set this up as a ratio
81 c / 37.5 % = x c / 100% Multiply both sides by 100%
81c/37.5% x 100% = x c c = cupcakes
81c x 100%/37.5% = x = 216 cupcakes order
Let θ be an angle in quadrant III such that cosθ=(−3/4). Find the exact values of cscθ and cotθ.
cscθ = - 4 /√[ 4^2 - 3^2] = - 4 /√ [ 7] = - [ 4√ ( 7) / 7 ] = -(4/7) √ [ 7]
cotθ = 3 / √ [ 7] = (3/7) √ [ 7 ]
Something is missing ...... how far did it descend on the ramp before the flat?
In quadrant III sin and cos are BOTH negative
sin^2 + cos^2 = 1
sin^2 = 1- c0s^2 = 1- 9/16= 7/16
sin =- sqrt 7 /4
csc = 1/sin = - 4 / sqrt 7 tan = sin / cos = - sqrt7/4 / -3/4 = 4 sqrt 7 /12 = sqrt7/3
Sorry....you wanted cot = 1/tan = 3/sqrt7
Is '2' the base, opposite of the 20 degree OR the 70 degree angle???
x = xo + vo t + 1/2 at^2 But in this case xo and vo are zero
x = 1527 = 1/2 (32.2) t^2
t = 9.74 seconds
Hypotenuse = 50 Leg 1 = 48 50^2 = 48^2 + L^@
50^2 - 48^2 = L^2
14 cm = L
Yep...any fraction in the form 1/n will repeat unless n can be factored solely in terms of 2 or 5 [or both ]
BTW....the maximum length of any such repeat will be n - 1 digits
You cant!!
Be right with you in a sec.....
3 7/20 * 1 3/4=
\(3\frac{7}{20}\times 1\frac{3}{4}=\frac{67}{20}\times \frac{7}{4}=\frac{469}{80}=5.8625\)
!
Length of diagonal = 4√3 cm
The short side is given by :
10 tan (27°) ≈ 5.095 = 5
35.274