All Answers 356028 Answers

8*2^2+(0/2) = 32

5-(-5)=5+5=10

lol

1-1=0

Trust me bro i feel ya cuz i have my maths final on Sunday

What is your question again?

There are 365 days in a year and in one day there are 24 hours so u do 

365*24=8760 hrs

6+6=12 0r

3+3+3+3=12 or 

3x4=12

Why is it not possible to divide by zero?

That is a good question :)

Try watching this you tube clip. :)

how do i find a real number?

Yea i am not sure,    

 If you found the imaginary number then maybe ther real number is in someone else's quarters.....

Mmm

Make sure you look under the bad, that is where my kids find most ot the things that they lose.  .....

(2x-5y)^2

\((2x-5y)^2\\ =(2x)^2-(2*2x*5y)+(-5y)^2\)

Now guest, you can have a try at finishing it :)

roberto, kendra, and imran painted a whole wall. roberto painted 2/5 of the wall and kendra painted 1/3

a)what fraction of the wall did imran paint?

b)each person painted a rectangle section of diffrent length. the wall is 30m long. how long was each person's section?

A

\(1-\frac{2}{5}-\frac{1}{3}=\frac{15-6-5}{15}=\frac{4}{15}\)

Imran painted \(\frac{4}{15}\) of the wall.

B

\(imran \ painted \ \frac{4}{15}\times 30m=8m \ of \ the \ wall.\)

\(roberto \ painted \ \frac{2}{5}\times 30m=12m \ of \ the \ wall.\)

\(Kendra \ painted \ \frac{1}{3}\times 30m=10m \ of \ the \ wall.\)

  !

How can you find the angles of a triangle if you have all the sides?

\(\begin{array}{|rcll|} \hline \cos{(B)} &=& \frac{1}{2c}\cdot \left(a+\frac{c^2-b^2}{a} \right) \\ \cos{(C)} &=& \frac{1}{2b}\cdot \left(a-\frac{c^2-b^2}{a} \right) \\ A &=& 180^{\circ}-(B+C) \\ \hline \end{array}\)

Zero. Because you are dividing 0 only one time. And you cant really chop up nothing so it remains nothing.

Just add them together !

A mole is 6.022 x 10^23      This is a fraction of a mole

3.02 x 10^23  / 6.022 x 10^23   =   3.02 / 6.022 = .50149 mole   (about a half of a mole)

I would use a calculator.....or a slide rule....or an abacus (maybe)....or ask someone else....or copy off of someone else !

LOL

Remember....a MOLE is just a QUANTITY...a COUNT of particles     6.022 x 10^ 23   particles ....could be electrons could be atoms   could be molecules

a MOLE of CO2   is 6.022 x 10^23 MOLECULES of CO2  to find out how much that weighs, you will need to refer to a periodic table of elements to get the atomic weight of Carbon (12.01)  and the atomic weight of Oxygen (16.0)

these weights are the number of grams in each MOLE of these ATOMS

ONE MOLE OF CO2 MOLECULES would then weigh  12.01 + 16 + 16   grams (becuse there are TWO atoms of Oxygen in each MOLECULE of CO2)

12.01 + 16 +16 = 34.01 gms   per MOLE (6.022 x 10^23) MOLECULES of CO2

You'll have to refer back to that diagram I asked you to commit to memory......look at it.    334 is TWO DEVIATIONS above the mean (the TOP of the curve)......how many per centage points are above this ????   Look at the bottom of the graph.....there are only two more percentages entered at TWO deviations ABOVE the mean.....see them?????   Those two added together are all of the scores that are above 334 (which is two standard deviations above 310 ---the top of the curve)

Got it????

a^2-1/3a+4 = 10

I will assume that you want me to solve ( a^2-1)/(3a+4) = 10

\(\frac{( a^2-1)}{(3a+4)} = 10\\ \frac{( a^2-1)}{(3a+4)} \times \frac{3a+4}{1}= 10\times \frac{3a+4}{1}\\ a^2-1= 30a+40\\ a^2-30a-41= 0\\ \triangle=900+164=1064=4*266\\ a=\frac{30\pm\sqrt{4*266}}{2}\\ a=15\pm\sqrt{266}\\ \)

OR maybe you really have stated correctly what you wanted...

\(a^2-\frac{1}{3}a+4=10\\ a^2-\frac{1}{3}a-6=0\\ 3a^2-a-18=0\\ \triangle=1+216=217\\ a=\frac{1\pm\sqrt{217}}{6}\)

If it is just simple interest (no compounding) then

Prt  would be the answer

8000(.05)(3)    would be the interest ADDED to your principle (8000)

(X^3+3x^2-x+4)/(x-1)

if

F(x)=X^3+3x^2-x+4

f(1)=1+3-1+4=7   the remainder is going to be 7  (I'll just use for checking purposes)

          x^2+4x +3

          __________________

x-1    |X^3+3x^2-x+4

           x^3- x^2

           -------------------

                 4x^2 -x+4

                 4x^2-4x

                 -------------

                         3x+4

                         3x-3

                          -----

                              7

\(\frac{(x^3+3x^2-x+4)}{(x-1)}=x^2+4x+3+\frac{7}{x-1}\)

Price = 350 (1 - .15)^y            where y = number of years

Here is a chart you will just have to memorize (below)

From 310 to 286 is TWO STANDATD DEVIATIONS down and 322 is ONE STANDARD DEVIATION above the mean....

As you can see this covers 13.6% + 34.1% + 34.1 % = 81.8 %  of the scores.

3x+6+3x=18

6x+6=18

6x=12

x=2