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THANK YOU!!!

8b + 2  = 10b    subtract 8b from both sides

2  =  2b            divide both sides by 2

1  = b

This is the formula you use to calculate the monthly payment:

PMT=PV. R.{[1 + R]^N/ [1 + R]^N - 1}

1 - The monthly payment is =$1,052.24. This amount, however, multiplied by 60 months=$63,134.14.

This last amount DOES NOT agree with any of your 4 choices. It is out by as much as $12,000, which is ridiculous!!. There is a major mistake somewhere. Look into it.

2- The monthly payment is=$1,352.90. The balance of the mortgage AFTER the 60th payment should be=$225,766.25. The amount of the balloon payment should be=$225,766.25 + $1,352.90=$227,119.14. Again, this amount DOES NOT agree with any of your 4 choices!!. However, I do see what your teacher is doing in this case, which is, strictly speaking, not accurate!!. He/She is taking the balance of the mortgage after the 61st. payment, which comes to=$225,401.07 + $1,352.90(one additional payment!!!!????) =$226,753.97, which comes to 62 payments, which agrees with your second choice!!. Why? I'm at a loss to explain the reasoning behind this very unusual and unconventional calculation!!. Talk to your teacher about it. Good luck to you.

3 = √ x  -  1    add 1 to both sides

4  =  √x          square both sides

16  = x

5n + 34n  = 2

39n  = 2     divide both sides by 39

n  =  2 / 39

If the dilation is centerd at the origin, we have

(-4,3 ) → (0 + 3(-4) ,  0 + 3(3) ) →  (-12, 9 )

And i wanted to let people hear the song that made me wanna move and my dad got a job there :P

Your a grandma!

Congrats

and thanks fo rlisening to it im moving to sweden

Thanks for sharing DR.  I really like to listening to other people's choices of music :)

Yes I did listen to it, I thought my granddaughter would love it :))

3375 / 225  = 15 theatres

14 choose any 8   = 3003 different groups

Anytime :)

Find the sum of 35 terms of an arithmetic series of which the first term is a and the fifteenth term is 9a.

\(t_1=35 \qquad t_{15}=9a\\ t_n=t_1+(n-1)d\\ t_{15}=t_1+(15-1)d=9a\\ a+14d=9a\\ 14d=8a\\ 7d=4a d=\frac{4a}{7}\\ S_n=\frac{n}{2}(2a+(n-1)d)\\ S_{35}=\frac{35}{2}(2a+(34)\frac{4a}{7})\\ S_{35}=\frac{35}{1}(1a+17*\frac{4a}{7})\\ S_{35}=35(a+\frac{68a}{7})\\ S_{35}=35a+5*68a\\ S_{35}=35a+340a\\ S_{35}=375a\\ \)

Sergio walked to and from school 3/5 of the days in one month. He got a ride to school on 7/8 of the remaining days. On the one remaining school day that month he stayed home with a cold. How many school days were there that month?

thx

it already is a decimal.

5 root 3

2) Find the coordinates from the foot of the perpendicular from the point(1,2) to the line 4x-3y+7=0

I assume this means "Where does the perpendicular from (1,2) to 4x-3y+7=0 intersect 4x-3y+7=0"

Gradient of 4x-3x+7=0   is    4/3

Gradient of the perpendicular is   -3/4

\(y=\frac{-3}{4}x+k\qquad sub\;\;in\;\; (1,2)\\ 2=\frac{-3}{4}*1+k\\ 2\frac{3}{4}=k\\ k=\frac{11}{4}\\ y=\frac{-3x+11}{4}\\ 4y+3x-11=0 \)

and prove that this touches the circle x2 +y2 -2x-4y+4=0.

\(x^2 +y^2 -2x-4y+4=0\\ (x^2-2x) +(y^2 -4y)=-4\\ (x^2-2x+1) +(y^2 -4y+4)=-4+1+4\\ (x-1)^2 +(y-2)^2=1\\ \text{This is a circle with centre (1,2) and radius 1}\)

Since (1,2) is the centre of the circle,  the line passes right through the middle of the the circle so it must intersect with it twice.

because lifes unfair :)