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okay thanks guys

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Yes. 2+2=fish

ADD THE WORK PLS

ADD THE WORK PLS

0.00000009338

The meaning of life doesn't matter. Al that matters is that you live your life well.

answer = 

Slightly larger than 7 3/4 ring size

$37.20 x 20/100 =$37.20 x 0.20 =$7.44 Tax on the ticket.

$37.20 + $7.44 =$44.64 total price of the ticket.

It is NOT clear what you want. write it clearly so we can help you.

When the ancient Greeks studied circles,they always got the same number whenever they did a couple of things,and that number they called pi.

What they did : measured the area of a circle and its radius. Then divided the Area  by the square of the radius. Or,if you like  ;  A/(r^2).   They always got the same number,pi.  You will  know this as the formula for the area of a circle A = pi  X (r^2)

They also got the same number if they measured the circumference and divided it by double the radius,this gives the formula for the circumference of a circle as        circumference = 2pi X radius.

It did  not matter what size the circles they measured were,they always got the same answer,and so they realised that the relationships were constant   -,and pi is one of the most well-known constants in maths and physics. NASA has computed its value to hundreds of decimal places,as pi is a vital constant in working out problems for space travel.

Is this what you mean? 2sin2x=-sqrt(3)???. if so, then:

Solve for x:
2 sin(2 x) = -sqrt(3)

Divide both sides by 2:
sin(2 x) = -sqrt(3)/2

Take the inverse sine of both sides:
2 x = (4 π)/3 + 2 π n_1 for n_1 element Z
 or 2 x = (5 π)/3 + 2 π n_2 for n_2 element Z

Divide both sides by 2:
x = (2 π)/3 + π n_1 for n_1 element Z
 or 2 x = (5 π)/3 + 2 π n_2 for n_2 element Z

Divide both sides by 2:
Answer: |
 | x = (2 π)/3 + π n_1 for n_1 element Z
 or x = (5 π)/6 + π n_2 for n_2 element Z

Example: 3^-4 =1 / [3^4] =1 / 81

what is the value of 30 squared to the 3rd power

(30^2)^3 =30^(2*3) = 30^6 =729,000,000.

Find the derivative of the following via implicit differentiation:
d/dx(y) = d/dx((1 - 5 x)/(2 + 3 x))
The derivative of y is y'(x):
y'(x) = d/dx((1 - 5 x)/(2 + 3 x))

Use the quotient rule, d/dx(u/v) = (v ( du)/( dx) - u ( dv)/( dx))/v^2, where u = 1 - 5 x and v = 3 x + 2:
y'(x) = ((3 x + 2) d/dx(1 - 5 x) - (1 - 5 x) d/dx(2 + 3 x))/(3 x + 2)^2

Differentiate the sum term by term and factor out constants:
y'(x) = (-((1 - 5 x) (d/dx(2 + 3 x))) + (2 + 3 x) d/dx(1) - 5 d/dx(x))/(2 + 3 x)^2
The derivative of 1 is zero:
y'(x) = (-((1 - 5 x) (d/dx(2 + 3 x))) + (2 + 3 x) (-5 (d/dx(x)) + 0))/(2 + 3 x)^2

Simplify the expression:
y'(x) = (-5 (2 + 3 x) (d/dx(x)) - (1 - 5 x) (d/dx(2 + 3 x)))/(2 + 3 x)^2
The derivative of x is 1:
y'(x) = (-((1 - 5 x) (d/dx(2 + 3 x))) - 1 5 (2 + 3 x))/(2 + 3 x)^2

Differentiate the sum term by term and factor out constants:
y'(x) = (-5 (2 + 3 x) - (1 - 5 x) d/dx(2) + 3 d/dx(x))/(2 + 3 x)^2
The derivative of 2 is zero:
y'(x) = (-5 (2 + 3 x) - (1 - 5 x) (3 (d/dx(x)) + 0))/(2 + 3 x)^2

Simplify the expression:
y'(x) = (-5 (2 + 3 x) - 3 (1 - 5 x) (d/dx(x)))/(2 + 3 x)^2
The derivative of x is 1:
y'(x) = (-5 (2 + 3 x) - 1 3 (1 - 5 x))/(2 + 3 x)^2

Expand the left hand side:
y'(x) = (-3 (1 - 5 x) - 5 (2 + 3 x))/(2 + 3 x)^2
Factor the numerator and denominator of the right hand side:
y'(x) = (-5 (2 + 3 x) + 3 (-1 + 5 x))/(2 + 3 x)^2
Cancel common terms in the numerator and denominator:
Answer: |y'(x) = -13/(2 + 3 x)^2

∑[n^n, n, 1, 1000]

sum_(n=1)^1000 n^n≈1.000368199144....×10^3000

We cannot see that pic, access is denied. 

\(p=\frac{F}{A}=\frac{255N}{0,75m^2}=340\frac{N}{m^2}\)