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Solve for x:
3 + sqrt(x + 4) = x

Subtract 3 from both sides:
sqrt(x + 4) = x - 3

Raise both sides to the power of two:
x + 4 = (x - 3)^2

Expand out terms of the right hand side:
x + 4 = x^2 - 6 x + 9

Subtract x^2 - 6 x + 9 from both sides:
-x^2 + 7 x - 5 = 0

Multiply both sides by -1:
x^2 - 7 x + 5 = 0

Subtract 5 from both sides:
x^2 - 7 x = -5

Add 49/4 to both sides:
x^2 - 7 x + 49/4 = 29/4

Write the left hand side as a square:
(x - 7/2)^2 = 29/4

Take the square root of both sides:
x - 7/2 = sqrt(29)/2 or x - 7/2 = -sqrt(29)/2

Add 7/2 to both sides:
x = 7/2 + sqrt(29)/2 or x - 7/2 = -sqrt(29)/2

Add 7/2 to both sides:
x = 7/2 + sqrt(29)/2 or x = 7/2 - sqrt(29)/2

3 + sqrt(x + 4) ⇒ 3 + sqrt(4 + (7/2 - sqrt(29)/2)) = 3 + sqrt(15/2 - sqrt(29)/2) ≈ 5.19258
x ⇒ 7/2 - sqrt(29)/2 = 1/2 (7 - sqrt(29)) ≈ 0.807418:
So this solution is incorrect

3 + sqrt(x + 4) ⇒ 3 + sqrt(4 + (7/2 + sqrt(29)/2)) = 3 + sqrt(1/2 (15 + sqrt(29))) ≈ 6.19258
x ⇒ 7/2 + sqrt(29)/2 = 1/2 (7 + sqrt(29)) ≈ 6.19258:
So this solution is correct

The solution is:
Answer: |x = 7/2 + sqrt(29)/2

One way as follows:

\(\frac{3-\sqrt x}{9-x}=\frac{3-\sqrt x}{(3-\sqrt x)(3+\sqrt x)}=\frac{1}{3+\sqrt x}\)

Hence limit as x tends to 9 is 1/6

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What is 61/100,00 in decimal form?

See the following pic :

We can divide this into three separate figures

Rectangle ABFE  with area  =  B * H  =  5 * 2  = 10 units^2

Triangle BCF with  B = 2  H= 2   and area  = (1/2)BH  =  (1/2)2*2  =  2 units^2

Triangle ECD  with B= 7   H = 4  and area = (1/2)BH = (1/2)(7)(4)  = (1/2)28 = 14 units^2

So.......the total area  = [ 10 + 2 + 14 ] units^2  =  26 units^2

thank you

thank you

What is 1 4|5 +3|10

Write it like this:

1 4/5 + 3/10 =

9/5 + 3/10 =

18/10 + 3/10 =

21/10 =2 1/10

Try this: type "abs(-5)".

You should bracket the terms that are ambiguous, such as:2/x^2-7x. Is it: 2 / (x^2) - 7? or 2/(x^2 - 7)?....etc., so that there is no question as to what you want.

8^x = 2    and we can write

(2 ^3)^x  = 2^1

2^(3x) =  2^1       now.......equate exponents

3x =   1          divide both sides by 3

x = 1/3

Why is 8^x=2 simplified to 1/3

8^x = 2 take the log of both sides

x log(8) = log(2)

x =log(2) / log(8)

x = 1/3

It's wrong. Cphil, please help!!!!!!1

Yep, that's correct.

i gotchu fam a is 18 b is 21 boy to easy 

I think you may mean " a difference of two squares"

(x^8 - 6561) =

(x^8 - 3^8)  =

( x^4 - 3^4) ( x^4 + 3^4)  =

[ (x^2)^2  - (3^2)^2 ]  [ (x^2)^2 + (3^2)^2 ]

So....it is a difference of  two squares