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\(2^{2n} = \frac{1}{64} \\ 2^{2n} = \frac{1}{2^{6}} \\ 2^{2n} = 2^{-6} \\ 2n = -6 \\ n = -3\)

2020

wut is this

(s^2t^-3)^5/6(s^6)^2

\(\Large\frac{(s^{2t^{-3}})^5}{6(s^6)^2}=\frac{s^{-30t}}{6s^{12}}=\frac{1}{6s^{12}\times s^{30t}}=\frac{1}{6s^{30t+12}}\)

  !

assuming s is a variable this would be the indefinite integral.

\(\int\frac{s^22}{6t^15}\;ds=\frac{s^23}{138t^15}+C\)

His average speed will be the total distance he traveled divided by the total amount of time it took him.

Find his total distance:

12 minutes is 12/60 hours, or 0.2 hours.

He went 15 mph for 0.2 hours, so the distance to the grocery store is 15(0.2) = 3 miles.

He went to the grocery store and back twice so his total distance was 3(2) = 6 miles.

Find his total time:

The first trip was 12 minutes.

He went twice as fast on the second trip so his time will be half as much. 12/2 = 6 minutes.

His total time is 12 + 6 = 18 minutes.

Average speed = 6 miles / 18 minutes

Average speed = 1/3 miles per minute.

Average speed = 20 miles per hour.

What is 2 feet 7 and 3/4 inches multiplied by 36 feet and 8 inches? Need fast answer not long explaination

\((2ft*\frac{12inch}{ft}+7\frac{3}{4}inch)\times(36ft*\frac{12inch}{ft}+8inch)\)

\(=31\frac{3}{4}inch\times440inch\)

\(=13970inch^2\) = \(97ft^2\ 2inch^2\)

  !

9.01 M^2

(2 + 7.75/12)(36 + 8/12)

= (127/48)(110/3)

= 13970/144

= 6985/72 feet²

≈ 97.01 feet²

Do you mean that the length of the side going up is 8 units and the length of the side going to the right is 8 units?

If that is the case and the shape you have is a rectangle, then the are is just base times height.

The base is 6 and the height is 8.

6 times 8 is 48. So the area is 48 square units.

the answer should be 3.

Thanks, MP......!!!!

Correct, DR  !!!!

162°  lies in the second quad.....it should take on a negative value for the cosine....

[ Note.....Math Guy.....you were in radian mode, rather than degree mode.......a common mistake !!!  ]