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\(2\div 0 = \infty\)

I am assuming that you mean 

For how many values of x is the function \(y=\dfrac{x-2}{x^2-7x+10}\) undefined?

As the denominator is a quadratic function, there are 2 values of x which makes the function \(y=\dfrac{x-2}{x^2-7x+10}\) undefined.

8 * 2 = 16

8 * 5 = 40

Please help!!!!!!!!!!!!!!

I love the hard-working but self-willed neddy.

The answer is "to eat it for dessert!!".

Algebraic solution of your problem gives the number of years as =6.07329856042 years.

Natalie was running a race with her friend. Natalie’s friend ran 23 miles of the race. Natalie ran 1.2 mph slower than her friend. If Natalie’s friend ran the race in 3 hours, and 12 minutes, how fast did Natalie run the race?

\(v_F=\frac{23miles}{3\frac{12}{60}h}=7.1875\ miles/h\)

\(v_N=7.1875\ mph-1.2\ mph=5.9875\ mph\)

\(t_N=\frac{s}{v_N}=\frac{23miles}{5.9857mph}=3h\ 50min\ 28.81sec\)

\(Natalie \ run \ the \ race \ in \ 3h\ 50min\ 28.81sec.\)

!

LOL same, though I like birds too, and fish, and lizards, and dogs, and.... Ok I love all animals.

lion and cats

I think when you say "12mph slower", I believe you mean "12 miles slower than her friend over the same distance of 23 miles"??!!. If so, then it means that when her friend finished the 23-mile run, Natalie was still 12 miles from the finish line. Therefore, Natalie's speed was:[23 - 12] / 3.2 hours =3.4375 mph. Then,the time it takes Natalie to finish the race would be:

23 / 3.4375 =6.69 hours, or about 6 hours and 41.4 minutes.

this one can, but it will be in scientific notation

3hr, 12minutes  =   3.2 hrs

And   Distance  / Time  = Rate....so

23miles / 3.2hours     =  7.1875 mph  =  rate of Natalie's friend

Thus....it's impossible that Natalie ran 12mph slower than this  !!!!!

its D 

just flip the line around

Adam is taller.....

Adam's height - Mark's height  =

[10 - 100tan (2.3)]  - [10 - 100tan(2.6) ]   = 

≈ [5.96ft   -  5.46 ft]   =

≈ .50  ft    .....    and Adam is ≈  6 inches taller

.

Ok so let's start by subtracting 15 from both sides.

so now its

-2x = -24

and now we divide both sides by -2

and now x = 12.

We are looking for the intersection of

y = 45000         and

y = 15000 [ (1.074)^t  + e^(.062t) ]

Here's a graph : https://www.desmos.com/calculator/zmejtzneea

The time is about 6 years....

Lol it IS good. 

(secΘtanΘ)/sinΘ  =

(1 / cos Θ) *  (sinΘ)/(cosΘ) * 1 /(sinΘ)  =

(1/cos^2Θ) * ( sinΘ/sinΘ)   =

sec^2Θ *  1   =

sec^2Θ

What is your issue?

6.67e-9  = 

6.67 x 10^-9   =

.00000000667

 3x^2-15x+k

This is a parabola.... the x coordinate of the minimum value  = -b/2a 

= 15/ (2(3) )  = 15/6  =

5/2

So...we have

1 = 3(5/2)^2 - 15(5/2) + k     simplify

1  = 3(25/4)  - 75/2  + k

1 = 75/4 - 75/2 + k

1 = -75/4  + k

4/4 + 75/4  = k   =  79/4

Here's a graph that confirms this : https://www.desmos.com/calculator/rzief47yod

It should be SHIFT + sin

Lol Sorry