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if your per hour salary is 45$ then number working hrs * 45 = 360

360 is your 1 days salary and 360 * 5 days = 1800$

im good cphill and guest

lol I could be better 😅 I'm in school rn

How are u??

Good....and you???

64x^2 - 16   factor

16 (4x^2 - 1)

16(2x + 1) (2x - 1)

P(a|b)

Rhombus

The correct answer should be 7.

Multiplication comes before addition.

A negative times a negative is a positive.

-2 * -2 + 3

4 + 3 = 7

I don't know what the other calculator is doing. Maybe it's thinking the negative signs are subtraction signs and it completely ignores the multiplication.

-2 - 2 + 3

-4 + 3 = -1

0.35 or .35

change it to 7/2*1/10 ull get 7/20

y - 10 = (4/3)(x-6)

Get it into y = mx + b form.

y - 10 = (4/3)x - (4/3)6

y - 10 = (4/3)x - 8

y = (4/3)x + 2

When it is in this form, the x coefficient is the slope.

4/3 is the slope.

4/3, put it in the form of y=mx+b ,, the m is the slope

I don't know. At all. But somehow I'm in algebra 1 (high math for my grade) lol idk help me 

13/20

\

(x-4)^2+8*(x-2)

\(\begin{array}{|rcll|} \hline && (x-4)^2+8\cdot (x-2) \\ &=& x^2-8x+16 +8x-16 \\ &=& x^2 \\ \hline \end{array}\)

Lol oops 😜

Solve 2 cos 2𝑥° = 1 for 0 ≤ 𝑥 ≤ 180.

\(\begin{array}{|rcll|} \hline 2 \cos (2x) &=& 1 \quad & | \quad : 2 \\ \cos (2x) &=& \frac{1} {2} \quad & | \quad \pm\arccos() \\ 2x &=& \pm\arccos( \frac{1} {2} ) +360\cdot k \qquad k \in \mathbb{Z} \\ 2x &=& \pm 60^{\circ} + 360^{\circ} \cdot k \quad & | \quad : 2 \\ x &=& \pm 30^{\circ} + 180^{\circ} \cdot k \\ \mathbf{x_1} & \mathbf{=} & \mathbf{30^{\circ}} \\\\ x_2 &=& -30^{\circ} + 180^{\circ} \\ \mathbf{x_2} & \mathbf{=} & \mathbf{150^{\circ}} \\ \hline \end{array} \)

help

11+ 22+ 33+ 44+ 55+ 66+ 77+ 88+ 99+ 110+ 121+ 132+ 143+ 154+ 165+ 176+ 187+ 198+ 209+ 220+ 231+ 242+ 253+ 264+ 275+ 286+ 297+ 308+ 319+ 330+ 341+ 352+ 363+ 374+ 385+ 396+ 407+ 418+ 429+ 440+ 451+ 462+ 473+ 484+ 495+ 506+ 517+ 528+ 539+ 550+ 561+ 572+ 583+ 594+ 605+ 616+ 627+ 638+ 649+ 660+ 671+ 682+ 693+ 704+ 715+ 726+ 737+ 748+ 759+ 770+ 781+ 792+ 803+ 814+ 825+ 836+ 847+ 858+ 869+ 880+ 891+ 902+ 913+ 924+ 935+ 946+ 957+ 968+ 979+ 990+ 1001+ 1012+ 1023+ 1034+ 1045+ 1056+ 1067+ 1078+ 1089+ +1100+ 1111+ 1122+ 1133+ 1144+ 1155+ 1166+ 1177+ 1188+ 1199+ 1210+ 1221+ 1232+ 1243+ 1254+ 1265+ 1276+ 1287+ 1298+ 1309+ 1320+ 1331

Arithmetic Sequence:

\(\begin{array}{|rcll|} \hline a_n &=& a_1+(n-1)\cdot d \quad & | \quad a_1 = 11 \qquad d = 11 \qquad a_n = 1331 \\ 1331 &=& 11 + (n-1)\cdot 11 \\ 1320 &=& (n-1)\cdot 11 \\ 120 &=& n-1 \\ \mathbf{121} & \mathbf{=} & \mathbf{n} \\\\ s_n &=& \frac{(a_1+a_n)}{2} \cdot n \\ s_{121} &=& \frac{(11+1331)}{2} \cdot 121 \\ s_{121} &=& \frac{1342}{2} \cdot 121 \\ s_{121} &=& 671 \cdot 121 \\ \mathbf{s_{121}} & \mathbf{=} & \mathbf{81191} \\ \hline \end{array} \)

A sample of 4 different calculators is randomly selected from a group containing

20 that are defective and

37 that have no defects.

Find the probability that at least one of the calculators is defective. Round to the nearest thousandth.

\(\begin{array}{|rcll|} \hline && \frac{ \binom{20}{1} \cdot \binom{37}{3} } {\binom{57}{4} } \\ &=& \frac{ 20 \cdot \frac{37}{3} \cdot \frac{36}{2} \cdot \frac{35}{1} } { \frac{57}{4} \cdot \frac{56}{3} \cdot \frac{55}{2} \cdot \frac{54}{1} } \\ &=& 4\cdot \frac{ 20 \cdot 37 \cdot 36 \cdot 35 } { 57 \cdot 56 \cdot 55 \cdot 54 } \\ &=& 0.39340776183 \\ &\approx& 0.393\quad (39.3\ \% ) \\ \hline \end{array} \)

Find the next three terms in the geometric sequence: 

6075,4050,2700,1800

\(\text{ratio } r = \frac{4050}{6075} = \frac{2700}{4050} = \frac{1800}{2700} = \frac23\)

\(a_4 = 1800 \\ a_5 = a_4 \cdot r = 1800\cdot \frac23 = 1200 \\ a_6 = a_5 \cdot r = 1200\cdot \frac23 = 800 \\ a_7 = a_6 \cdot r = 800\cdot \frac23 = 533.\bar{3} \\\)

(2027! + 2028!)/(2028! - 2029!) = (2026!! 2027!! + 2027!! 2028!!) / (2027!! 2028!! - 2028!! 2029!!), where !! = Double factorial. OR: (2027! + 2028!)/(2028! - 2029!) = (Γ(2028) + Γ(2029))/(Γ(2029) - Γ(2030)), where Γ = The Gamma function.

What is 5 and 1/3 divided by 1 and 7/9

\(\begin{array}{|rcll|} \hline && \dfrac{5 + \frac13 } { 1 + \frac79 } \\\\ &=& \dfrac{ \frac{3\cdot5 + 1}{3} } { \frac{9\cdot 1 + 7}{9} } \\\\ &=& \dfrac{ \frac{16}{3} } { \frac{16}{9} } \\\\ &=& \frac{16}{3} \cdot \frac{9}{16} \\\\ &=& \frac{9}{3} \\\\ &=& 3 \\ \hline \end{array}\)

Let v be the vector from initial point P1 to terminal point P2.

Write v in terms of i and j. P1= (-1,2), P2= (-9,-5)

\(\begin{array}{|rcll|} \hline \vec{v} &=& \vec{P_2} - \vec{P_1} \\ \vec{v} &=& \binom{-9}{-5} - \binom{-1}{2} \\ \vec{v} &=& \binom{-9-(-1)}{-5-2} \\ \vec{v} &=& \binom{-9+1}{-5-2} \\ \vec{v} &=& \binom{-8}{-7} \\ \vec{v} &=& -8\cdot i -7\cdot j \\ \hline \end{array} \)

how to you tell when the next leap year is?

1700 is divisible by 4 but not a leap year
1800 is divisible by 4 but not a leap year
1900 is divisible by 4 but not a leap year

Leap year:
We have a leap year if  the year  is divisible by 4
and ( the year is not divisible by 100 or the year y is divisible by 400 )

Example:
y= 2020
2020 : 4        remainder 0  okay
2020 : 100    remainder \(\ne\) 0 okay
-> 2020 is a leap year

What is -3a^2? (Negative three a squared)

\((-3a)^2=(-3)^2a^2=9a^2\\~\\ -(3a)^2=-3^2a^2=-9a^2\\~\\ -3a^2 \quad \text{can not be simplified}\)