log10(10^2)=2
log10 100 = 2 in exponential form, if we have loga b = m. we can write a^m = b....so
10^2 = 100
[m - 3] / 4 = [m + 1 ] / 3 cross-multiply
3 [ m - 3 ] = 4 [ m + 1] simplify
3m - 9 = 4m + 4 add 9 to both sides, subtract 4m from both sides
-1m = 13 divide both sides by -1
m = -13
give a specific example
0
x log (5) - y log (2) we can write
log (5)x - log (2)y and this simpilfies to
log (5x / 2y)
Anything multiplied or divided by 0 is 0.
Touche.
Keep it positive? Gee willikers, that’s tough
While studying physics, I learned that light travels faster than sound. This explains why some people appear bright until they speak?
"Difficult roads often lead to beautiful destinations."
As a fraction, it is already in its most reduced form.
As a mixed number, it is:
\(\frac{32}{3} = 10\frac{2}{3}\)
Thanks, HSC.....
Recursive rule
an+1 = 4 * an
Explicit rule
an = 2 (2n - 1)
4th term = 2 (2n - 1) = 2 (2*4 - 1) = 2 (7) = 128 = 4 * 32
5th term = 4 * 128 = 512
6th term = 4 * 512 = 2048
The frist two have been answered.
For the third one...
Divide -2/3 on both side (or multiply by -3/2)
Then add 2 on both sides.
Result: -4
an + 1 = 3*an and the nth term is given by:
5 * 3 (n - 1) so the 13th term is 5 * 3 (13 - 1) = 5 * 3 12 = 2,657,205
First. Divide both sides by 2/5 (or multiply by 5/2, same difference)
Then subtract both sides by 7.
Result, n = 15/2 - 7
27 what?
I think this is supposed to be :
[sin x cos y + cos x sin y] / [ cos x cos y- sin x sin y] = [cot x + cot y]/ [cot x cot y - 1]
Work on the left side dividing every term by sin x sin y
[ cot y + cot x] / [ cot x cot y - 1] and this equals the right side
percy and annabeth
