All Answers 356786 Answers

You should probably dye it. You can pull it off.

1+1=window.

Hi ppl 

keep.

keep it

You subtract -6 from 9. If you subtract a negative from something, then it becomes a positive. (so 9+6). 9+6 is equal to 15, so -15+15 (Or you can do 15-15). So -15+9--6= 0

Center is at (h, k), therefore (-7, 13).

me    

Nothing really. Same old, same old

What is your question then?

The answer is 2

The equation for a circle is in the form of (x^2)+(y^2)=(r^2)

where r=radius of a circle thus implying the radius of said circle will be sqrt(169) which is equivalent to 13.

Oh thank heaven!

anyone get that joke? Lol 

thanks!

You could also do this way:

20/13 =  1.538462...... This is the number of doublings in 20 years

2^1.538462 x 5,000 =14,524 - projected population in 20 years.

50/13 = 3.8461538....   This is the number of doublings in 50 years.

2^3.8461538 x 5,000 =71,908 - projected population in 50 years.

1 kg(9.8m/s2)

\(1kg \cdot 9.81\frac{m}{s^2}\cdot \frac{Ns^2}{m}=9.81N\)

\(Mass \times acceleration = force\)

  !

nah u're wrong it's actually 7/11

do not interfere

Im alive.

Only the guest is dead. He is from the h**l. JK XD

y = 1/2 x + 4.

This is a straight line when plotted as a graph. Its gradient is 1/2 and its y-intercept is 4. 

y = 1/2 x + 4 using -1, 0, 1, 2? I don't know which variable is -1, 0, 1, 2 do you want. x = -1, 0, 1, 2 or y = -1, 0, 1, 2?

I only can tell you that you should substitute the numbers into either x or y(depends on which you want), and then compute the value of the other variable.

Yea. There is an admin called "admin". lol

I guess you need to use trigonometry.

I assume that 1500 mile north is the straight line distance, not the arc length.

Therefore Let theta degrees N is the latitude of point P

tan theta = 1500/3960

theta approx equal 21 

The latitude of point P is \(21^{\circ}N\)

Thanks Heureka,

I was wondering how this would be done.  

I did think of substituting x=tan(z) but I didn't get very far with it.   

Now I shall take a good look at your answer :))