Btw dixongirl35, you posted this as an off-topic question.

-5 + n/3 = 0

-5 + n/3 + 5 = 0 + 5

n/3 = 5

3*n/3 = 3*5

n = 15 :D

N e M means N * 10^M

So -3.015e-08 means -3.015 * 10^(-8) = -0.00000003015

18 sin b = 8 sin 110

sin b = 4/9 * sin 110

b = 24.69 degrees.

sin 110 is assumed sin 110deg.

22/5 + 21*2

= 4.4 + 42

= 46.4

:)

With steps.

~The smartest cookie in the world.

What are you doing...... I do not understand what you typed.

But for "41.40962211 is 41 degrees 24 minutes and 34.64 seconds", I totally agree.
I just do not understand what are you doing in the math part, can you please explain more?

~The smartest cookie in the world.

GingerAle.... Yeah he is kinda rude, I admit, but he is a great "gadget" on the forum...... 
 

For  

"Oh, my . . . This is great! We need another old gasbag! A companion for the forum’s Banker –one who articulates more, but is even less intelligible." and

"I hope he stays around. We stylish, superior trolls really relish rare, refined dinning of preposterously presumptuous pretentious phrases in our smorgasbord.  We also like to listen to the villains in the old Scooby-do cartoons while we enjoy our meal.", it is just because a guest is giving incomplete answers and thinking that his answer is actually the best. I think he is just stating the truth that the guest's answer is not a very good answer, but in a harsh way.

For

"Note to Blarney Banker: If you don’t understand this, I can try to dumb it down for you. However, I’d probably just be wasting my time and annoying the pịg",

he is just angry about a guest doing wrong stuff.....

For 

"Who wrote this brain-dead question? Does a retired Blarney Banker teach your class?", he is angry about the teacher of the guest wrote a question that does not make sense at all.

For

"I just tested both with 2+2. Both gave the answer of 4. The Calculator and Excel seem to work fine. So, this means you are an imbecile of low order.  If you give an example, then someone may explain why. Then you will know to which low order of imbecile you belong", I don't see where you find this, can you give a link?

But I guess that's because there are always some guess who are always TOO bored and they have nothing to do and say that 2 + 2 = 5 and then try to mess people who are new to math up. I have no patience to those people too and I think this comment is appropriate to stop people from messing up stuff. If I were him(her?) I would do that too.

For 

"Rusty armor, dull sword, and Bad manners. He probably doesn’t even know the multiplication tables."

I don't know where did you find this too, can you also give a link for proof?

These comments are usually because he is angry about people doing stuff wrong, as he hates people doing wrong stuff and wants others to do correct stuff instead of doing things wrongly.

He did answer many questions and helped people, so he is really a gadget on the forum.

Hope you understand the reason for him to say such words.

~The smartest cookie in the world.

thank you very much

it is afternoon now but i had a very good night and day too 

hope you have the same

:D

It is about night for me..... XD

So hope I will have a good sleep tonight :)

Hi GingerAle,

Thanks for another very long response, which you this time used mostly to make fun of me, and talk about everything other than what I was talking about.

We have like 10 topics going on by now, while I only answered the many different points of your first message, because I found it appropriate after you had written such a long response - not to make this thread about any and everything.

I'm still interested in knowing the possibility of 19 being so in tune with the numerical values of this sentence, if anyone serious is willing to answer this question.

I'm afraid in order to show the values of each number, one will have to know the arabic letters of which there are 28. The lowest value according to my knowledge is 1, and the highest is 1000. 1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 20, 30, 40, 50, 60, 70, 80, 90, 100, 200, 300, 400, 500, 600, 700, 800, 900, 1000. Each letter has one and only one of these values.

Therefor as I said, one of those sequences are made up of the numerical value of the letters making up the 19-letter sentence, each followed immediately by it's sequence number. This gives us a 62-digit sequence, that is divisible by 19 (21602403143053065718309200108114012501311430152001681710184019).

Changing one letter in the sequence, will subsequently change the order of numbers, leaving a very small possibility of the sequence still being compatible with 19. Please also count in the other sequences, and how they are made up.

I would like a serious answer regardless of what one might think of my world view. And if one would like to discuss world views I suggest we do that in another forum, since this is one of math, and frankly the different disciplines should be held apart for as long as it takes to finish the task concerning them. They compliment each other of course, but when your opinion biological or cosmological opinion becomes an obstacle to your mathematical abilities, you can't claim to have practiced transdisciplinary science in a constructive way. If still, one would like to discuss it, I'd gladly give the first cup of coffee for that conversation.

Multiples of 8: 8, 16, 24, 32, 40, 48, 56, .....

Multiples of 14: 14, 28, 42, 56, .......

Therefore LCM(8 , 14) = 56

7/9,4

= 7/(47/5)

= 35/47 <-- final answer as a fraction

Something Mathematical to do.

\(\begin{array}{llcl} \int \limits_{x=0}^{\infty} { \frac{1}{ (x+\sqrt{1+x^2})^2 } \ dx}\\\\ & \text{substitute:}\\ & \boxed{~ x=\tan(z) \\ dx = ( 1+\tan^2(z))\ dz \\ ~}\\ & \text{new limits:}\\ & \boxed{~ z=\arctan(0) \Rightarrow z = 0 \\ z=\arctan(\infty) \Rightarrow z = \frac{\pi}{2} \\\\ ~}\\ =\int \limits_{z=0}^{\frac{\pi}{2}} { \frac{1+\tan^2(z)}{ \Big(\tan(z)+\sqrt{1+\tan^2(z)}\Big)^2 } \ dz} \\ & \boxed{~ 1+\tan^2(z) = \frac{1}{\cos^2(z)} \\ ~}\\ =\int \limits_{z=0}^{\frac{\pi}{2}} { \frac{1}{\cos^2(z)}\cdot \left( \frac{1}{\frac{1}{\cos^2(z)}+ \tan^2(z)+2\cdot \frac{\sin(z)}{\cos^2(z)} } \right) \ dz} \\ = \int \limits_{z=0}^{\frac{\pi}{2}} { \frac{1}{1+2\cdot \sin(z) + \sin^2(z) } \ dz} \\ = \int \limits_{z=0}^{\frac{\pi}{2}} { \frac{1}{ \Big(1+\sin(z)\Big)^2 } \ dz} \\ & \text{substitute:}\\ & \boxed{~ t=\tan(\frac{z}{2}) \\ dt = \frac12 \cdot \left( 1+\tan^2(\frac{z}{2}) \right)\ dz\\ =\frac12 \cdot (1+t^2)\ dz \\ ~}\\ & \text{new limits:}\\ & \boxed{~ t=\tan(\frac{0}{2}) \Rightarrow t = 0 \\ t=\tan(\frac{ \frac{\pi}{2}}{2}) \Rightarrow t = 1 \\\\ ~}\\ = \int \limits_{t=0}^{1} \frac{2\ dt}{1+t^2} \cdot \left( \frac{1}{ \left(1+ \sin(z)\right)^2 } \right) \\ & \boxed{~ \sin(z) = \frac{2t}{1+t^2} \\ ~}\\ = \int \limits_{t=0}^{1} \frac{2\ dt}{1+t^2} \cdot \left( \frac{1}{ \left(1+ \frac{2t}{1+t^2}\right)^2 } \right) \\ = 2\cdot \int \limits_{t=0}^{1} \frac{1+t^2}{1+4t+6t^2+4t^3+t^4} \ dt\\ = 2\cdot \int \limits_{t=0}^{1} \frac{1+t^2}{(1+t)^4} \ dt\\ \end{array}\)

\(\begin{array}{llcl} & \text{Partial fraction decomposition:}\\ & \boxed{~ \begin{array}{lcll} & \frac{1+t^2}{(1+t)^4} &=& \frac{A}{1+t} + \frac{B}{(1+t)^2} + \frac{C}{(1+t)^3} + \frac{D}{(1+t)^4} \\\\ & 1+t^2 &=& A\cdot (1+t)^3 +B\cdot (1+t)^2 +C\cdot (1+t) +D \\ (1)\quad t=-1 : & \Rightarrow 2 &=& D \\ (2)\quad t= 0 : & \Rightarrow -1 &=& A+B+C \\ (3)\quad t= 1 : & \Rightarrow 0 &=& 8A+4B+2C \quad | \quad : 2 \\ & 0 &=& 4A+2B+C \\ (4)\quad t= -2 : & \Rightarrow 3 &=& -A+B-C \\\\ (2)+(4) : & -1+3 &=& 2 B \qquad \Rightarrow B =1 \\ (3)+(4) : & 0+3 &=& 3A + 3B \quad | \quad : 3 \\ & 1 &=& A + B \quad | \quad B=1 \\ & 1 &=& A + 1 \qquad \Rightarrow A =0 \\ (2): & C &=& -1-A-B \\ & &=& -1-0-1 \qquad \Rightarrow C =-2 \\ \end{array} ~}\\ \end{array}\)

\(\begin{array}{llcl} = 2 \int \limits_{t=0}^{1} \left( \frac{1}{(1+t)^2} -2\cdot \frac{1}{(1+t)^3} +2\cdot \frac{1}{(1+t)^4 } \right) \ dt\\ = 2 \int \limits_{t=0}^{1} \frac{1}{(1+t)^2}\ dt -4 \int \limits_{t=0}^{1} \frac{1}{(1+t)^3}\ dt +4 \int \limits_{t=0}^{1} \frac{1}{(1+t)^4}\ dt \\ = 2 \left[ -\frac{1}{1+t} \right]_{t=0}^{1} -\frac{4}{2} \left[ -\frac{1}{(1+t)^2} \right]_{t=0}^{1} +\frac{4}{3} \left[ -\frac{1}{(1+t)^3} \right]_{t=0}^{1} \\ = 2 \left[ -\frac{1}{2} -(-1) \right] -\frac{4}{2} \left[ -\frac{1}{4}-(-1) \right] +\frac{4}{3} \left[-\frac{1}{8}-(-1) \right] \\ = 2 \left[ -\frac{1}{2} +1 \right] -2 \left[ -\frac{1}{4}+1 \right] +\frac{4}{3} \left[-\frac{1}{8}+1 \right] \\ = 2 \cdot \frac12 -2\cdot \frac34 +\frac43 \cdot \frac78 \\ = 1 - \frac32+ \frac76 \\ = \frac66 - \frac96 +\frac76 \\ = \frac{13}{6} - \frac96 \\ = \frac46 \\ = \frac23 \\ \end{array}\)

\(\begin{array}{llcl} \int \limits_{x=0}^{\infty} { \frac{1}{ (x+\sqrt{1+x^2})^2 } \ dx} = \frac23 \end{array}\)

That's good! Well have a good rest of your day!😊

I am fantastic and feeling astonishingly glorious

8 = 2^3

14 = 2 x 7

So, the LCM =2^3 x 7 = 56.

The answer is 8.53. The word pie is simply pi and e put together. When you have two variables together you mulitpuly it just so happens that these values make a word. 

First, you have to find out the annual average growth:

2^(1/13) =1.054766...... - 1 x 100 =5.4766% This is the average annual growth rate.

1.054766^20 x 5,000 = ~14,524 expected population of the town in 20 years.

1.054766^50 x 5,000 =~71,908  expected population of the town in 50 years.

I HAVE THE ANSWER!!!

0.75268817204

It will be 2/11

Hahahahahaa You have got to be kidding! GingerAle will love this. BTW,  ball busting GingerAle is a girl. 

Given a past population of 45234000 and a present population of 51321000 and the growth rate is 0.5 how do .i calculate the number of years.

51,321,000 / 45,234,000 = 1.005^n

1.1345669.... = 1.005^n

n = Log(1.1345669) / Log(1.005)

n = ~25.3 years.

error: enter a more detailed question