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Too soon

what is the riddle

Two brothers were watching a horror film on video late one night. One brother dozed off and dreamed that he was being chased by the crazy man from the movie, who was trying to k**l him. In the dream, he hid in a cupboard. There was no sound except his heart pounding, and he had no idea where his crazed captor was. He was terrified! At that moment, the video finished, and his brother put his hand on the shoulder of his sleeping sibling to wake him. The shock at that tense moment was enough that the sleeping brother suffered a massive heart attack and died instantly. True or false?

Oki 

I don't see your posts about them

WHAT IS IT THAT NO MAN DID YET SEE

THAT NEVER WAS 
BUT ALWAYS IS TOO BE?

\(\frac34*3.14*0.75^3= 0.993515625\)

But, this doesn't really look like the type of input to find the volume of a cylinder.

Did you mean this:     \(\frac43*3.14*0.75^3\)   ...which is approximately the volume of a sphere with a radius 0.75         ?

You're here in this world today to choose the right thing, the right way, or the right path. You've got to make use of your time, set a goal that will benefit you. Dedicate your life to something and do it well. 

I hope that helps! 

xxx 

thanks grammer natzi

x*4*3x = 4x*3x=12x²

2x-9=21-4x  |+4x

6x-9=21       |+9

   6x=30       | :6

     x=5

It's spelt: Certain**

40%=0,4

85*0,4=34

You save $34.

i belive that 9/11 was a inside job also

If you want to calculate 7/8 * 216 you can do this without a calculator. Simply look if there are numbers that are both in the numerator and denominator. Since you can divide 216 with 8 you can change the calculation to become 7*(216/8) = 7*((27*8)/8) = 7*27 = 189. 
 

Another way to see if you can easily multiply 7/8 with 216 is to divide 216 in its prime numbers.

216=2*108=2*2*54=2*2*2*27=8*27

7/8*8*27 = 8/8*7*27=7*27=189

We don't need to do further than to the point where we see that the numerator and denominator both contain the same number. Then you simply remove the 8's from the numerator and denominator :) 

suck balls

consider the intersection of the function; x2+y-8=0 and x+y=2.

what is the greater of the x-coordinates of the points of intersection?

\(\begin{array}{|lrcll|} \hline (1) & x^2+y-8 &=& 0 \\ & y &=& 8-x^2 \\\\ (2) & x+y&=& 2 \quad & | \quad y = 8-x^2 \\ & x+8-x^2 &=& 2 \\ & x^2 - x - 6 &=& 0 \\ & x &=& \frac{1\pm \sqrt{1-4\cdot(-6)} }{2} \\ & x &=& \frac{1\pm \sqrt{1+24} }{2} \\ & x &=& \frac{1\pm 5 }{2} \\ \\ & x_1 &=& \frac{1+5 }{2} \\ & x_1 &=& \frac62 \\ &\mathbf{ x_1 } & \mathbf{=} & \mathbf{3} \\\\ & x_2 &=& \frac{1-5 }{2} \\ & x_2 &=& -\frac{4}{2}\\ &\mathbf{ x_2 } & \mathbf{=} & \mathbf{-2} \\ \hline \end{array}\)

The greater of the x-coordinates of the points of intersection is 3

3 vergins are still being hunted