All Answers 358291 Answers

examp. 12:00 start Ali                              Bakar:  4km ->1h

             12:30 start Bakar                         6km->xh    <=> x=3/2h <=> x=90 min +12:30= 2:00 

                                                                 arrived at the same time so Ali arrived at 2 so he do:

                                                                  6km->2h

                                                                  ykm->1h <=>y=3km so 3km/h is the Ali's average speed!!!

 I hope you understand!!!

1,2,3,4,5,6,9,10,12,15,18,20,30,36,45,60,90 and 180! 

type    asin(  )

or press   2nd    sin   

what a cheater!!! nvm me and the other two guys, we totally just happened to stumble upon this, we didn't look it up at all no no no no no no

OK, forget the answer in #8. I think this the accurate answer, which is exactly the same as Bank LMI calculation:

Up to $5,000 is Nil:

From $75,000 to $479,000 is: $1,050[which is from $5,000 - $75,000] + $3.5 x $404,000/100[which is from $75,000 to $479,000] =$1,050 + $14,140 =$15,190 - trasfer duty to the Government.

OK, I will take a crack at this one, which is exactly the same as "transfer duty" on the house. I made a small mistake on that one which I have adjusted.

$75,000 to $479,000 =$404,000 is: $1,050 + $3.50 x $404,000/100 =$15,190 - which is LMI for a house of $479,000.

Not more than $5,000

Nil

More than $5,000 up to $75,000

$1.50 for each $100, or part of $100, over $5,000

$75,000 to $540,000

$1,050 plus $3.50 for each $100, or part of $100, over $75,000

$540,000 to $1,000,000

$17,325 plus $4.50 for each $100, or part of $100, over $540,000

More than $1,000,000

$38,025 plus $5.75 for each $100, or part of $100, over $1,000,000

Additional duty of 3% applies to acquisitions of residential land by foreign persons (including companies and trusts) from 1 October 2016.

There is a toggle button at the bottom left of the calculator.

\(\sqrt{74}\approx8.60232526704\)

r≈3.53cm

The following formula can be used to find the area of a sphere:

Let V= volume

Let r= radius

\(V=\frac{4}{3}\pi r^3\)

Now, let's plug the information we know back into the equation. We know that the volume equals 184cm³ ,so let's use that and then isolate r, the radius:

\(24units^2\)

Here's another way to find the area of this figure. The area for area for a rhombus is the following:

Let A= area of rhombus
Let d1= length of a diagonal of rhombus

Let d2= length of the second diagonal of rhombus

\(A=\frac{1}{2}d_1d_2\)

How will we find the lengths of the diagonals? Use the distance formula! That formula is:

\(d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}\)

Let's find the length of d1 first by substituting and then simplifying.

\(d_1=\sqrt{(-2-(-2))^2+(-8-0)^2}\)

\(d_1=\sqrt{0^2+(-8)^2}\)

\(d_1=\sqrt{0+64}\)

\(d_1=8\)

Let's find d2 by substituting and then simplifying:

\(d_2=\sqrt{(-5-1)^2+(-4-(-4))^2}\)

\(d_2=\sqrt{(-6)^2+0^2}\)

\(d_2=\sqrt{36+0}\)

\(d_2=6\)

Now, plug d1 and d2 back into the area formula for a rhombus:

\(\frac{1}{2}*8*6=4*6=24units^2\) 

Isn't it beautiful how three unique and different methods arrive one to the same final answer? It fascinates me...

there are 12 women in a group of 21.

if i pick one person at random in the group, what is the probablity they will be a woman.

answer is 12/21

well if you draw a line to -3,-4 and say that line is the hypotenuse 

then the line drawn from that point to -3,0 is a hight of 4

and the line drawn from 0,0 to -3,0 is a base of 3

seems like a pythrn triple 3,4,5 so hypotenuse is 5

sine is opp/hyp or 4/5, so sin theta is 4/5

sqrt of 64 is 8

sqrt of 81 is 9

so inbetween those so probably about 8.6

if they are similar then setup as ratios.

531              ?

------   =    --------

1475          3875

cross multiply to solve

We can solve this with a proportion

( 3/8) / (3/4)  =   x  / (1/3)         where x is what we need ....cross-multiply

(1/3) (3/8)  =  (3/4) x

(3 /24)  =  (3/4)x

(1/8)   = (3/4)x     multiply both sides by 4/3

(4/3) (1/8)   = x  =   4 / 24   =   1 / 6  cups of blueberries

Let   f(x)  = 2 u * v    where

u  = sin (4x)

v= sin^-1 (x)   =  arcsin (x)

Using the product and chain rules :

f ' (x)  =   2 [  u ' * v +  u * v ' ]

So

f  ' (x)  =  2  [   4cos (4x)* arcsin (x)  +  sin (4x) *   1 / √ (1 - x^2 ) ] =

8cos(4x)arcsin (x)  +  2 sin (4x) / √ (1 - x^2 )

Here's one other method based on hectictar's pic......

The intersection of two grid lines represents a "point" in the following theorem

So.......the area of this figure  =

(Number of interior points in the figure) + (number of boundary points ) / 2  - 1    =

( 23)   + (4 ) / 2   - 1   =

23 +  2  - 1   =

24  sq units

[ This is known as Pick's  Theorem ]

Considering that an average elephant weighs between 2.7 tons to 4.5 tons, and eats an average 300 lbs per day minus the exception this would be a circus elephant, the elephant would weigh between 2.5-4.0 tons without the acrobat. Adding the acrobat would add an additional 110-140 lbs,(depends on if it's a fit male or female), the weight would add up to be 3.25 tons(+ or - .75tons ) + 125lbs (+ or - 15lbs) would come to the average Elephant weight. 

P.S: I was bored

\(\frac{\text {arc length}}{\text{circumference of circle}}=\frac{120^{\circ}} {360^{\circ}} \\~\\ \frac{\text{arc length}}{8\pi}=\frac{120^{\circ}} {360^{\circ}} \\~\\ \begin{array} \ \text{arc length}&=&\frac{120^{\circ}} {360^{\circ}}*8\pi \\~\\ &=&\frac13*8\pi \\~\\ &=& \frac{8\pi}{3} \\~\\ &\approx& 8.4 \, \text{miles} \end{array}\)

The derivative of the inverse function is given by :

g'(x)  =   1 / [ f ' (g (x) ) ]

Note that  ( 3, 4)  is on  " f " so   (4, 3)  is on   " g "    so.....g (4)  = 3

So

g ' ( 4)  =  1 / [ f ' ( g (4) ) ]  =   1 / [ f ' (3) ]  =   1 / [ 5 ]   =   1 / 5 

Someone on here might be able to help!

What is your question?    

K(H)  =  - ( x^2 + 1)^2 + 4  ....so

-(x^2 + 1)^2  + 4  = 0      

-(x^2 + 1)^2   = -4   multiply through by -1

(x^2 + 1)^2   = 4     take the pos/neg square roots

x^2 + 1  =  ± 2

So...either

x^2 + 1  = 2          subtract 1 from both sides

x^2  = 1         take both square roots

x = ± 1

Or

x^2 + 1  = -2    subtract 1 from both sides

x^2  =   -3    take both square roots

x = ± (√3) i

And those are the 4 solutions

slope = (change in rise) / (given change in run)

A vertical line runs 0 ..so

slope = (change in rise) / 0

And, anything divided by 0 is undefined

Therefore,

The slope is undefined.

This actually isn't a square since the sides are not perpendicular....It is a rhombus!

Here's what it looks like:

It is made up of two congruent triangles that split the rhombus in half.

(I'm looking at the top and bottom halves, but there are also left and right halves.)

area of rhombus = 2 * area of one of these triangles

                           = 2 * (1/2) * base of triangle * height of triangle 

                           = base of triangle * height of triangle

                           =       [ 1 - -5 ]       *  [ (1/2) * (0 - -8) ]

                           = [ 6 ] * [ 4 ]

                           = 24   sq. units