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I am not sure. You would probably have to find out strictly from a moderator like Melody or CPhill.

\(x^2+6x+5\)

Determine a, b, and c values.

\(a=1, b=6, c=5\)

Multiply a by b

\(a*b=1*5=5\)

What factors of 5 add up to 6?

Since there are only two factors of 5, 1 and 5, determine which variations combine to 6.

In this case it would be a +5 and a +1.

\((x+5)(x+1)\)

Ok, thank you!

You are correct, NediaMaster.....!!!!

Ne...lol

305-154=s

s=151

-(x-(y-x))+(9x-(3x+4y))

-(x-y+x)+(9x-3x-4y)

-(x+x-y)+(6x-4y)

-(2x-y)+(6x-4y)

-2x+y+6x-4y

4x-3y

Not great at Physics......but here's my best shot......!!!!

1)A child and his father are 89m apart. They start walking towards each other. A mosquito that flies at 5.1m/s moves back and forth between the child and his father until they meet. If the mosquito started off from the same position as the child, and given that the child walks at 1.2m/s, while the father is twice as fast, what was the total distance covered by the mosquito? Keep in mind that the mosquito, child and the father start moving at the same time.

Note that the child walks at 1.2m/s and the father walks twice as fast  = 2.4 m/s.....so....the distance that they close between themselves every second  must be   (1.2 + 2.4) m/s  = 3.6 m/s

So......it will take them  89m / 3.6 (m/s)  = (445 /18 )  seconds  in which to meet each other

Since the mosquito is in the air the same amount of time...it must cover a distance of  (445/18)s * 5.1 m/s  ≈ 126.1 m  

2)A subway moves between two stations. The first third of the distance is covered in uniform motion, at 20m/s. During the second third, the velocity of the train is maintained constant at 20km/h [N]. For the rest of the trip, the train was in uniform motion and the speed was 50km/h. If the train was moving towards north for the whole trip, what was the average speed of the train?

Convert km/h to m/s

20 km/h  = 20 * 1000 / 3600  =  50/9 m/s

50 km/h  =   50 * 1000 / 3600  = 125/9 m/s

Note  that distance / rate  = time.....call the total distance that the train traveled, D

So....the time of the first leg of the trip can be denoted as  (1/3)D / 20 m/s   =  (1/60)D  =  D/60

And the time of the second leg of the trip can be denoted as  (1/3)D / (50/9)m/s     =  (3/50)D  = 3D/50

And the time of the third leg of the trip can be denoted as (1/3)D / (125/9)m/s  =(3/125)D  =  3D/125

So........we have that

Total Distance  / Total Time  =  Average Rate  .....so......

D  / [  D/60  + 3D/50  + 3D / 125]     which can be factored as

D / [ D ( 1/60 +  3/50  + 3 / 125)  ]  =

1 / [ 1/60  + 3/50   + 3/125]  =

1 /  [  (25  + 90  + 36) / 1500 ]  =

1 / [151 / 1500 ]  =

1500 / 151  ≈   9.9 m/s   =   average rate

3)How fast does an arrow must be shot straight in the air, in order to cover 22.3m during its 2nd one-second time interval? Use gravitational acceleration as 9.8m/s^2.

Using

y  = V * t  - (1/2) (9.8) * t^2

Where    y  is the height after some t seconds   and V is the initial velocity

After the first second the arrow has reached a height  of y1

y1  = V(1) - (1/2)(9.8) (1)^2

y1  = V  - 4.9           (1)

After the next second the arrow has reached a height of y1 + 22.3m

y1 + 22.3  = V * (2)  - (1/2) (9.8) * (2)^2

y1 + 22.3  =  2 V  - 2 (9.8)

y1  =  2V  - 2(9.8) - 22.3

y1  = 2V  -  41.9        (2)

Equate  (1)  and (2)

V  - 4.9   =  2V  -  41.9       add  41.9 to both sides   subtract V from both sides

37  = V     =   37 m/s  =  the initial velocity

1)

If \((2x+3y)(3y+2x)=z\), according to the given information, and \(x=3.2\) and \(z=457.96\), just plug those values in to solve for y:
 

2)

This is a system of equations. I usually refrain from using the elimination method here because it is difficult to showcase. Therefore, I will use the substitution method. 

I will solve for y in equation 2:
 

Plug this value for y into equation 1 and then solve for x.

Now, plug x=-4 into either equation and solve for y. I'll choose equation 2 because it look easier to do:

Therefore, the coordinate where both lines intersect is \((-4,2)\).

Note that we really have that

(2x + 3y)^2 = z   ...so....

(2(3.2)  + 3y)^2  = 457.96       simplify inside the parentheses

( 6.4 + 3y)^2  = 457.96          take the positive and negative square roots 

6.4 + 3y   = ±√457.96            subtract 6.4 from both sides

3y  = ±√457.96 - 6.4             divide both sides by 3

y  = [ ±√457.96 - 6.4 ] / 3 

So we have that   y  = [√457.96 - 6.4 ] / 3   = 5

And        y  = [ - √457.96 - 6.4 ] / 3   ≈  -9.2667

2.    3x+5y= -2   multiply through by 3     →  9x + 15y  =  - 6        (1)

      -2x-3y=  2    multiply through by 5    → -10x - 15y  =  10        (2)

Add (1) and (2)   and we get that

-1x  = 4      divide both sides by -1

x  = -4

Subbing this back into any of the equations for x to find y, we have

  3 (-4)  + 5y  = -2

-12  + 5y  = -2        add 12 to both sides

5y  = 10                divide both sides  by 5

y  = 2      

3. sqrt3(250/1024)

I'm guessing that this might actually be   ∛  [ 250 / 1024]  ....if so, we have....

∛ [ (2 * 125)  / ( 2 / 512) ] =

∛ [  (2 * 5^3)  / ( 2 * 8^3) ]   =

(5/8) ∛ (2/2)  =

(5/8)∛ 1  =

(5/8)

9^0.5 = 3

Guest above is correct :)

3 is the answer to 9 to the power of 1/2

pie^2

pie is a food, can't square it

pi^2

pi^2 = 9.8696044010893586

Well as we know that pi is used to find area by multiplying the radius squared times pi also that pi is used to find area and circumference of a circle. Pi r squared..

The language of your question is a little bit confusing. You say "for a credit card the minimum balance owing is $25 or 1.5% of the balance owing." I think what you mean to say is "for a credit card the minimum PAYMENT owing is $25 or 1.5% of the balance owing." 

If that is what you meant, then the minimum PAYMENT, in this case, would be $25, since 1.5% of the balance owing would be: $800 x 1.5% =$12, which is less than $25.

too complicated!

thermometer, clock, stopwatch

is it 54

Your equation is false the way you have written. Check your numbers carefully.

This is the formula you would use to calculate the FV:
FV=P{[1 + R]^N - 1/ R}

But before you do that, you must match the compounding period of the interest rate, which is semi-annual, to the periodic deposits, which are compounded quarterly. We know that 6% is compounded semi-annually, which means every 6 months you would multiply by 1.03. Now, we can turn this into quarterly compound as follows: 1.03^1/2 =1.0148891565 -1 =0.0148891565. This is the quarterly interest rate that you would use in the above formula.

FV = 75,000 x {[1 + 0.0148891565]^(4*4) - 1 / 0.0148891565}
FV = 75,000 x {[       0.2667700813876161] / 0.0148891565}
FV = 75,000 x            17.91707148673..........
FV =$1,343,780.36 - This is what Ryan will have saved in 4 years.

The pattern goes like this: 0, 5, 12, 21, 32, 45

and I need to find out the formula for this pattern

\( \begin{array}{lrrrrrrrrrrrrrrrrr} & {\color{red}d_0 = 0} && 5 && 12 && 21 && 32 && 45 && \cdots \\ \text{1. Difference } && {\color{red}d_1 = 5} && 7 && 9 && 11 && 13 && \cdots \\ \text{2. Difference } &&& {\color{red}d_2 = 2} && 2 && 2 && 2 && \cdots \\ \end{array}\)

\(\begin{array}{rcl} a_n &=& \binom{n-1}{0}\cdot {\color{red}d_0 } + \binom{n-1}{1}\cdot {\color{red}d_1 } + \binom{n-1}{2}\cdot {\color{red}d_2 } \\ \end{array}\)

\(\begin{array}{|rcl|} \hline a_n &=& \binom{n-1}{0}\cdot {\color{red} 0 } + \binom{n-1}{1}\cdot {\color{red} 5 } + \binom{n-1}{2}\cdot {\color{red} 2 } \\ &=& (n-1)\cdot 5 + \frac{n-1}{2}\cdot \frac{n-2}{1} \cdot 2 \\ &=& 5n - 5 + (n-1)(n-2) \\ &=& 5n - 5 + n^2-3n+2 \\ &=& 2n +n^2 -3 \\ \mathbf{a_n} & \mathbf{=} & \mathbf{-3+2n+n^2} \\ \hline \end{array} \)

\(\begin{array}{|rcll|} \hline \mathbf{a_n} & \mathbf{=} & \mathbf{-3+2n+n^2} \\ a_1 &=& -3+2*1+1^2 \\ &=& -3+2+1 \\ &=& 0\ \checkmark \\\\ a_2 &=& -3 +2*2 + 2^2 \\ &=& -3+4+4 \\ &=& 5\ \checkmark \\\\ a_3 &=& -3 + 2*3 + 3^2 \\ &=& -3 + 6 + 9 \\ &=& 12\ \checkmark \\ \ldots \\ \hline \end{array}\)

I was answering the problem also Max, but realized he asked for an equation and didnt know how to do that? like (x+(5+(nth+2)))but that isnt correct

If I am reading this correctly, p is the amount of hours that Mr Ahmad used the hall for and q is the total price.

100+15p=q Would be the formula you would use because 15 is the price per hour and p is the amount of hours

Now set q to 490 and you have

100+15p=490

-100

       15p=390

         p=26

So he would have used the hall for 26 hours

i.)100+15p=q

ii.)p=26