Let's go through the process again, shall we?
Let x represent one of the numbers. Then 15-x is the other number. Knowing this, the equation becomes x(15−x)=63.
x(15−x)=63 | Distribute. |
15x−x2=63 | Subtract 63 from both sides. |
−x2+15x−63=0 | I like to divide by -1 out of habit. |
x2−15x+63=0 | In this case, this quadratic cannot be factored. I'll use the quadratic formula here. |
x=−(−15)±√(−15)2−4(1)(63)2(1) | Let's do some simplification here. |
x=15±√225−2522 | |
x=15±√−272 | I see an issue here, do you? This is probably why you were unable to come up with a solution. The square root of -27 results in a nonreal answer. |
This means that no quadratic equation with real solutions can have property aforementioned, which is a sum of 15 and a product of 63.