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Math humor?

I'll give it a "shot", but don't (var x)pect me sqrt(4) get it 90 degrees.

I'll give it a  " shot "  

CAUTION :     MATH HUMOR DETECTED

I'll give it a  " shot "   

Define units for the additional practice time and the time spent working on shooting skills.

hours  and  hours

Then enter a variable for the additional practice time. . . (additional to the 18 hours)

x                        --  this is the expression for Additional Practice Time.

. . .and use this variable to write an expression for the time spent working on shooting skills.

$\frac34$(x + 18)           -- this is the expression for  Time Spent Shooting.

Question 1

For Additional Practice Time, we are given  51

So Time Spent Shooting  =  $\frac34$(51 + 18)  , which  =  51.75

Question 2

For Time Spent Shooting, we are given  55.5

Additional Practice Time  =  x   and   $\frac34$(x + 18)  =  55.5

$\frac34$(x + 18)   =   55.5           Multiply both sides of this equation by  4/3

x + 18   =   74                   Subtract  18  from both sides

x   =   56   =   Additional Practice Time

Question 3

For Additional Practice Time, we are given  46

So Time Spent Shooting  =    ..... (Can you finish it??)

[ sin x  * tan x ]  + cos x  =   sec x

[sin x *  sin x / cos x ]  +  cos x  = sec x

[ sin^2 x  /  cos x]  + cos x =  sec x            ...  get a common denominator on the left

[sin^2 x  /  cos x]  +  [cos^2 x / cos x ] =  sec x        .... sin^2 x  + cos^2 x = 1

[ sin^2 x  + cos^2 x] / cos x    =   sec x

1 / cos x   =  sec x

I see they reposted the question and I found out I read it wrong. I agree with @CPhill that its A.

Yes. I googled it. The internet never fails.

I wish I could help, but I haven't learned about cosecants and cotangents.

Sorry!

:)

do you an email where i can send you the pic of all the problems. 

a is correct

To see this.....

Jessie must take at least 30 minutes

So

x/2  >=  15      multiply both sides by 2

x >= 30

1. senx tgx + cosx = secx

2. cosecx=senxcotgx cosx

3.(senx+cosx)^2+(senx = cosx)^2=2

those are some but i still have another ones. 

what are the problems?

I wasn't. I thought I was helping 

Why did you post this question twice?

if you are going to try to give false answers please stop promagma

But it said the x goes to jesse?