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Well at least you are honest enough to openly admit that your whole point in being here is that you are cheating.

Most people here give their time for free becasue they are generous people who want to help others to learn.

Yes I find YOU offensive and I find it offensive that some people here want to faciliate cheating!

1/2/34 works, too. 

Unless there are others that we have not counted, there are 8.

The link works for me, but the unsuspecting user gets redirected to a popup box requesting for a username and password. Sorry, can't help you!

This problem requires knowledge of the midpoint formula. For any two coordinates, \((x_1,y_1)\) and \((x_2,y_2)\), the coordinate of their respective midpoint is located at \(\left(\frac{x_1+x_2}{2},\frac{y_1+y_2}{2}\right)\). 

Let's plug in those coordinates, shall we?

If you think about it, the midpoint formula (unlike others) should make sense logically; after all, all you are doing is finding the average of the given coordinates. If this is unclear, maybe this image will help facilitate your understanding of the midpoint formula. When I learned this formula, it definitely helped me. 

Let's see if I can steer you in the right direction here. If you need more assistance, just ask! Someone will probably fill you in!

As aforementioned, a parallelogram, by definition, is a quadrilateral wherein its opposite sides are parallel. Opposite angles congruency is a known property of parallelograms, but we will assume for the problem's sake that you don't know that already! Here is a simple diagram for you to reference!

I have extended the segments. Because opposite sides are parallel, this means that \(\overline{WX}\parallel\overline{ZY}\) and \(\overline{WZ}\parallel\overline{XY}\). You can start by trying to identify the relationship between angles located on the same segment (\(\angle Z\) and \(\angle Y\), for example). Then, do that process again for a segment that intersects with the segment you identified the relationship. Therefore, if you picked to compare \(\angle Z\) and \(\angle Y\), then identify the relationship between \(\angle X\) and \(\angle Y\). Use your knowledge of relations when parallel lines are involved. Once you find the relationship of these angles, see if you can relate all the information you gathered together. 

Again, I am not necessarily giving you the answer here, but I hope you will sit down and try to think this through. If you need additional help, I will be glad to give it!

Hmm, you seem offended. I apologize if you took offence to my words. Yes, I am cheating, why? Because I honestly can't find a reason to learn geometry, or how it would help me in life. 

Sounds like you passed because CPhill gave you the answers.

What a clever boy you are, you are learning to cheat your way through life.  What a lot we can learn from the internet!

Students always blame teachers, the only thing wrong with your teacher is the lazy, cheating student that he /she has.

As you can see, CPhill is just peachy!

What is this? Is there something in the air? Normally this syrupy, sweet spray of pre-mating pheromones happens closer to springtime.    

9.  Not as bad as it looks

these points form a trapezoid  with a top base = 5   a bottom base = 7   and a height = 2

So....the area  is

(height)/2  *  ( sum of the bases)  =

(2)/2  *  ( 5 + 7)  =     1 * 12   =    12 units^2 

Here's a pic  :  https://www.desmos.com/calculator/c3knzz9qii

10.   pi r^2

        pi r^2 h

        1/3

11. Volume of a sphere  =  (4/3) (3.14) (diameter / 2)^3  =  (4/3) (3.14) (4/2)^3  ≈ 33.5 cm^3 

thank you CPHILL how are you?

I WOULD say the same thing...!!!

1. Give me just one, logical scenario where I, personally would ever, ever in life need to utilize geometry? 

2. I found this website, maybe three or four months ago, and in the time i've spent here, I noticed that i'm not the only one posting questions expecting others to answer for me (and i've told Cphill once before that i'm not good at this type of mathematics (maybe because my teachers didn't explain it well.) and that he is pretty much the only reason I passed with all my classes having good grades last semester.) so why is it supposedly wrong when I do it?

3. Although I am unspeakably grateful for whoever answers, it's not like i'm forcing them to answer, and if they genuinly have a problem with what I'm doing, I ask no, I bag of you, do not answer and I will find another way to figure out the problem.

Thank for your time.

so the answer is 7?

CPhill has a different attitude to me but I see a list of questions llike this and it seems to me that this is probably a test and you are asking us to take your test or do your assignment for you.  Even if this is not the case you are certainly not asking for anyone to teach you anything!

I would not do any of them and I know many other people here would feel the same way.

You re not asking anyone to teach you anything - you are just asking us to help you cheat!

5. length  =  √  [ 48^2  + 61^2  ]  =  √ 6025   ≈  77.6 ft  

6. equal

    pi r^2 h

7.    [ 7x - 40 ] / 18   = 25 / 15

       [ 7 x - 40 ] / 18 =  5 / 3    multiply both sides by 18

        7x  - 40   =   (5/3) * 18

        7x  -  40   =  30      add 40 to both sides

        7x   =    70           divide both sides by  7

         x   = 10 

8.   √ [ 19^2 - 13^2  ]  =  √ 192  ≈  13.9 

( 7k - 3)  ( k^2 - 2k  +  7)  =

7k ( k^2  - 2k  +  7 )  =          7k^3  -   14k^2   +  49k

+                                       +

-3 ( k^2 - 2k  + 7)   =                          -3k^2    +    6k   -   21

_____________                  _________________________

                                             7k^3   -   17k^2  +  55k   -  21

I'll answer a few....but not all 33   !!!!

1.   XZ / YZ  =  DF / EF     ⇒   15 / 10  =  DF /  8     multiply both sides by  8

     (8 *15) / 10  =  DF

      120 / 10  =  DF  =   12 

2.   diameter

      circumference

      pi

      diameter

3.  SAS Similarity Theorem

4.   The center of  the circle  is  ( 2, - 1)

And the radius is  √  [  ( 3 - 2)^2  +  ( -1 - 1)^2 ]  =  √ 5

So...the area of the semi-circle is   5pi/ 2  =  5(3.14)/2  = 7.85 

And  one side of the quadrilateral is 2√5

And the other dimension is √ [ ( 1 - 3)^2  + ( 2 - 1)^2 ] =  √ 5

So...its area  is  2√5 *√ 5  =  10

So...the total area is   [ 7.85 + 10 ]  units^2  =  17.85 units^2  =  17.9 units^2

3x+7=5x+1