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Mar 5, 2018
 #1
avatar+2446 
+2

This puzzle has a very elegant solution to it!
 

Actually, I think the best way to think about this one is to think two-dimensionally first! We have 3 points that we place on a circle! 

 

 

I have picked arbitrary points for A, B, and C. I want to determine the probability when the three points form a triangle wherein the center is included. No matter what three points you pick, there are four options

 

Option 1: Point A, Point B and Point C are where they are in the diagram.

Option 2: Point A is moved to the other side of line, Point B stays and Point C stays

Option 3: Point A stays, Point B moves to the other side of line, and Point C stays

Option 4: Point A moves to the other side of the line, Point B moves to the other side of the line, and Point C stays

 

In these 4 cases, only one of the situations has a polygon that includes the center, so for a circle, the probability is \(\frac{1}{4}\).

 

Actually, let's go down to one dimension! Let's just worry about a segment.

 

 

There are two possibilities.

 

1) Point B is on the left of O

2) Point B is on the right of O

 

In this case, there is 1 case that results in the center being included, so the probability is \(\frac{1}{2}\).

 

If a one-dimensional case yielded \(\frac{1}{2^1}\) and the two-dimensional case yielded \(\frac{1}{2^2}\), then it would seem logical to me to assume that the three-dimensional case would be \(\frac{1}{2^3}=\frac{1}{8}\). In fact, if you try the cases again, you will see that this is the case.

 #1
avatar+2446 
+1

I think this question is one where some people might want to pull out their hair in frustration. I suggest gathering all your information into an organized table. 

 

  Number of Rooms Painted Rate Time  
Paulo        
Irina        
Paulo + Irina        
         

 

We may not be able to fill in all the information, but that is OK! Do not forget what the end goal is! The end goal is to figure out how much time it will take if Paulo and Irina work together. This is the information we know:

 

  • Irina painted 1 room
  • Irina painted that room in 9 hours
  • Paulo painted the same room
  • Paulo painted that room in 8 hours
  • Together, Paulo and Irina will paint one room

Now that we know all this information, let's fill in the table. 

 

  Number of Rooms Painted Rate Time  
Paulo 1   8 hours  
Irina 1   9 hours  
Paulo + Irina 1      
         

 

Now, what is the painting speed of Paulo? I think you would agree that Paulo can paint at 1 room per 8 hours. This is the rate for Paulo! We can use the same logic for Irina. Irina paints at a speed of 1 room per 9 hours. Let's fill that information in!

 

  Number of Rooms Painted Rate Time  
Paulo 1 \(\frac{1\text{ room}}{8\text{ hours}}\) 8 hours  
Irina 1 \(\frac{1\text{ room}}{9\text{ hours}}\) 9 hours  
Paulo + Irina 1      
         

 

In order to fill in the rest of the table, we will have to introduce variables! I will use "x" to represent the number of hours it takes for Paulo and Irina collectively to paint this room. This means that the rate of them together is \(\frac{1\text{ room}}{x \text{ hours}}\). Let's fill that in, as well!
 

  Number of Rooms Painted Rate Time  
Paulo 1 \(\frac{1\text{ room}}{8\text{ hours}}\) 8 hours  
Irina 1 \(\frac{1\text{ room}}{9\text{ hours}}\) 9 hours  
Paulo + Irina 1 \(\frac{1\text{ room}}{x\text{ hours}}\) x hours  
         

 

We can assume that, if Paulo and Irina work together at their individual rates, then the rate will be the sum. 

 

Therefore, \(\frac{1}{8}+\frac{1}{9}=\frac{1}{x}\). Let's solve this!
 

\(\frac{1}{8}+\frac{1}{9}=\frac{1}{x}\) The best way, I believe, to solve this equation is to multiply by the LCM of the denominators. in this case, that number would be \(72x\).
\(9x+8x=72\) Add the like terms.
\(17x=72\) Divide by 17 on both sides.
\(x=\frac{72}{17}\approx\text{4.24 hours}\)  
   

 

Therefore, the correct answer choice is the last one (which is really just a manipulation of the equation I created).

 #2
avatar+105 
+1
Mar 5, 2018

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