Yeah lol
It's fine you can say my name
haha you already had D
I really think it is. I don't wana say your name on here...
Is that actually how you solve it....seems too easy lol
so its D
and the second one? That first one was tricky.
Uh idk...
Nvm I got it, it's D
np so i took πr2h and then i did 12*24*16 and that gave me 4608 then divided by 35.34 and got 130.390 so your answer would be 130 then
Are we in the same class? lol I think I know your picture...
The first one is a little tricky
If ABC is similar to FDE...then
AB BC AC
__ = ___ = ___
FD DE FE
Notice that DE is 1/2 of BC
DE = 2
BC = 4
FE is 1/2 of AC
AC = 8
So....FE = 4
And note that (2,1) is 4 units from E
So (2,1) = F
Do you mind explaining how you got that answer?
i believe it is 371
hold on im calculating
#1 no #2 no #3yes #4 yes
Each side of P'Q'R' is twice that of its corresponding side of PQR
So
P'R'
___ = 2 is true
PR
Also
P'Q'
____ = 2 multiply both sides by PQ
PQ
P'Q' = 2PQ subtract 2PQ from both sides
P'Q' - 2PQ = 0 is also true
i belive it is b or c
im thinking A and B
np m8
Yay! Thanks!
cool because if you multiply the inner box cordinates by 1.5 you get 3
You are correct !!!!
P'Q' 12 units 3
___ = _______ = __ = 3
PQ 4 units 1
i belive i speak for cphill when i say np
thank you so much!