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Jeff you are one day older than Kebab! How does it feel to be younger than Jeff Captain?

We know that the formula to find the area of a parallelogram is b*h, so in the first figure, we know that the base is 20cm and the area of 320cm^2. So the height is, 320/20=16. Now, we find the relationship between 20 and 25

20cm=25cm

16cm=?

1cm=25/20

16cm=25/20*16=20

So, the area is 25*20=\(\boxed{500}\)

Thanks! :)

Happy b-day captain kebab🍟

9.

Either an odd number or an even prime number.

Well, the only even prime number is 2. Everything else is divisible by 2, making it not prime.

So, we know on a 16 sided die that the numbers 1, 3, 5, 7, 9, 11, 13, and 15 are on there and apply to the odd number portion.

We have 8 numbers plus 1 extra number. 9 numbers in total, so divide 9 by 16.

9/16 = 0.5625

Rounded to the thousandths, it's 0.563.

10. 

Now, in this, we are NOT going to look at the Freshman, Sophomore, or Junior sections, as it is given that they are a Senior.

Our denominator will be 16+15+7, which is 38

Now we take however many preferred evening classes (7) and divide that by 38

7/38 = 0.1842105263157895

Rounded to the nearest thousandth, the answer is 0.184.

I don't know a whole lot about statistics, but maybe this chart can help. It's what I used to determine my answer.

A seems like the most likely answer to me.

The 80 people surveyed are the sample and statistic, which is used to create an estimated measurement for the whole population.

I'm seeing about 29% to 30% of respondants paying more than 700 a month.

Hello!! The answer is B. 75 bags.

Happy Birthday!! I hope that you have a wonderful birthday!!

33/60 reduces to 11/20

\({33 \over{60}} = {11 \over{20}}\) This is because 33 AND 60 can be divided by 3, which gives us 11 and 20

1.

For this, you'll use factorials. 

So, to find the possible orders, you have to do 6!. This is the same as 6*5*4*3*2*1.

6! = 720

So, the answer is 720.

2. 

You can actually do this on the calculator as well! Use nPr(n, r). n is the number on the left side, and r is on the right.

nPr(9, 5) = 15,120

So your answer is 15,120.

Hope this helped!

Solution:

\(E= Z_c \sqrt{\frac{\hat{p}(1-\hat{p})}{N}} \tiny \text{ (E is the margin of error. } Z_c \text{ is the critical value for the confidence level. } \hat{p} \text { is portion of interest.)}\\ \small \text {Arrange and solve for (N) to find the minimum sample size} \\ N= \left( \frac {Z_c /100}{E} \right)^{2} \hat{p}\left(1-\hat{p}\right) \\ \small \text {For 95% confidence }Z_c \small \text { } = 1.96\\ N= \left( \frac {1.96}{0.07} \right)^{2} \ * \ 0.68\left(1-0.68 \right) \; \ = \; \lceil{170.60}\rceil \Leftarrow \small \text {Round up to next integer}\\ \text {Minimum sample size }\mathbf {171}\\\)

Additional information:

For this question, the population is assumed to be above 20,000 (because no population is specified), well above what would be needed for a (US) high school population that averages 860 students per school, with the highest at 1500. For schools with these populations, the sample minimums calculate to 145 and 154 persons respectively. At 171 samples, the margin of error for these schools drops to 6.25% and 6.50% respectively.   

GA

Do you know what "inequality" is? And where is it in your expression 724 - x  +  18x  -  36 ??!!

8, 7, 6, 5, 4, 3, 2, 1, and 0.

1)  No one will shake hands with themself or their spouse so I can put a X in each of those pairs

2)  Now, let AH be the one that shakes 8 hands

3)  Now all have shaken AH hand axcept for his wife so his wife must be the only one to shake no hands

4) Let BH be the one to shake 7 hands

5) now all have shaken 2 hands already except for BW so she must be the one to shake just one hand

6) Let CH be the one to shake 6 hands

7) Now they have all shaken 3 hands except for CW so she must be the one to shake only 2 hands.

8)Let DH be the one to shake 5 hands

9) which means that D wife shakes 3 hands

Which now leaves E husband and E wife to shake 4 hands each.

That is, John and his wife shake 4 hands each  :)

Like so:

1. Do you mean "p is a prime greater than 3"?

2. Where is the question? Ok, so we add 1+1/3+1/3+...+1/(p-1), what is the question? You didn't ask me to solve anything.

C’mon guys, one of you should be smart enough to solve this...

(Definitely not me)

Pizzas

There are 14 possible toppings.

There are 14 ways to chose one topping

There are 14C2 ways to choose 2 toppings

...

There are 14C14 = 1  way to chose all 14 toppings.

Add them all together to get the number of possibilities.

If you think it is relevant you can add 1 which is the number of ways you can make a pizza with no toppings. 

Prob of guessing correctly is 1/total.

But not all topping choices would be equally likely so it is not really that simple.

thank you!

Hey! This question is from Alcumus!