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18/2=9*3=27

The same with this one!!.

Is your question missing something??

With 2 in the middle, you have = 2 numbers[1 x 2] - 120, 121

With 3 in the middle, you have = 6 numbers[2 x 3] - 130, 131, 132, 230, 231, 232.......and so on.

With 4 in the middle, you have = 12 numbers[3 x4]

With 5 in the middle, you have = 20 numbers[4 x 5]

With 6 in the middle, you have = 30 numbers[5 x 6]

With 7 in the middle, you have = 42 numbers[6 x 7]

With 8 in the middle, you have = 56 numbers[7 x 8]

With 9 in the middle, you have = 72 numbers[8 x 9]

So, you have a total of =2 + 6 + 12 + 20 + 30 + 42 + 56 + 72 = 240 "monutain numbers"

Note: Make sure you check them to see if I skipped any.

Can somebody translate this into proper LaTex, please? Thank you.

Let  (h, k)  be the center of the circle

And the distance  from this point to each  of the points  will be  equal  (the radius)

So  we have this equation

( h - - 7)^2  + (k - 0)^2  =  ( h  - 7)^2  + (k - 0 )^2

(h + 7)^2    =  ( h - 7)^2

h^2 + 14h + 49  =  h^2 - 14h + 49

14h  =  - 14 h

28h  = 0

h  = 0

And we can solve for k, thusly

(0 - 7)^2  + ( k -0)^2  =   ( 0  - - 3)^2  + (k - 4)^2

49  + k^2  =  9  + k^2 - 8k + 16

49  = 25  - 8k

8k  =  25  - 49

8k  = - 24

k  = -3

So......the center of the circle  is   ( 0, - 3)

And the radius  is  given by  √  [ (0 - 7)^2  + ( -3 - 0)^2 ]  =  √ [ 49 + 9] = √58

So... the equation  of  the circle is

(x - h)^2  + ( y - k)^2  = r^2

( x - 0)^2  +  ( y  - - 3)^2  = 58

x^2   +  ( y + 3)^2  = 58

Here is a pic :  https://www.desmos.com/calculator/m2ugumny98

I got it!

Since the line  y  = -x  + 4  has a slope of -1, then the line containing CD has a negative reciprocal slope  = 1

Therefore....the  slope of this line is

(4 - 0)  / ( m - k)  = 1

4  =  m - k

4 + k  =  m

Now...the height of the trapezoid is  4

And the length of  one base  is  k - - 1  =  k + 1

And the length of the other base  is 4 + k

So....the area of the trapezoid can  be represented as

(1/2) height   [ length of base 1  +  length of base 2  ]   =  34

(1/2) 4  *   [ ( k + 1)  +  ( 4 + k)  ]   =34

2  *  [  2k + 5 ] = 34

2k + 5   = 17

2k  =12

k  = 6

Here  is a pic :

An earlier Latex coding thread 

I am just joining some of the sticky notes together :)

This is some interest questions dated 26th sept 2016