All Answers 358203 Answers

Here is a graph:

Lets figure out the standard equation for a circle by completing the square

x^2-10x+25    + y^2-4x+4  = -12 +25 + 4

9x-5)^2  + (y-2)^2 = 17                                     center is h, k  = 5,2    

We want a straight line frome center through 9,3  to new center (so the circles will be tangent at 9,3)

5,2   to  9, 3    is  a change of  4,1      add that to 9, 3   to get    13,4

SO the identical tangent circle is

(x-13)^2 + (y-4)^2 = 17

6 is da answer

Two identical circles touch at the point P(9,3) 

one of the circles has equation x^2 + y^2 - 10x - 4y +12 = 0

find the equation of the other circle 

Right mouse click
Copy graphic
Insert into a Word document
then you can see it.

Add 2y to both sides; subtract 7 from both sides; double each term in the  resulting equation.

Multiply numerator and denominator by the complex conjugate of 1-2i; namely by 1+2i. 

Note that (1-2i)(1+2i) = 1 + 4 = 5; i.e. it no longer depends on i. 

See if if you can take it from there.

This is a miniscule written question. 

Just type it in!

NOTE:

There is a problem with the image viewer at present.

If you cannot see the images then follow the instructions(by CPhill and Hectictar) here

None of your choices provide the correct solution to what you have written!

3ⁿ⁺² + 3ⁿ⁺³ - 3ⁿ⁺¹ → 3ⁿ⁺¹(3¹ + 3² - 3⁰) → 3ⁿ⁺¹(3 + 9 - 1) → 11*3ⁿ⁺¹ 

I think you must have meant  3ⁿ⁺² / (3ⁿ⁺³ - 3ⁿ⁺¹)  → 3¹ / (3² - 3⁰) → 3 / (9 - 1) → 3/8   (where 3ⁿ⁺¹ has been factored out of the terms in both numerator and denominator).

Perhaps this graph will help:

Yes I think your answer is correct  (The image is the right half plane)

I followed your link but question 5 is different, am I missing something?

Sorry EP you are right. Your answer is good.     

Solution:

\(\text {Hugo can receive a maximum of 600 points for all tests. }\\ \text {The lowest “B” score is } (0.80 * 600) = 480 \text { points. }\\ \text {The highest “B” score is } (0.899 * 600) =539 \text { points. }\\ \text {Total points for the first four tests are } (82) + (88) + (91) + (83) = 344 \\ \text {For a “B” grade, the final score (F) must have a range of }\\ (479-344) \ge (F) \lt (540-344)\\ \hspace{2.6em} (135) \ge (F) \lt (196)\\ \; \\ \text {Answer “K” exceeds this range. }\\ \)

GA

I think it is correct, Melody.      Thnx   ~EP

You have made a little error EP

The largest one is x+1   (not x+2)

Diagram 6

now use cosine formula to finish it.

I have done it and was going to present my answer but since it is a comptetition I should leave some for you to do.

Hint:  there is a square root in the answer.

Have fun :)

diagram 5

Diagram 4

Diagram 3